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Zinaida [17]
3 years ago
10

How to convert 7 2/5 into a improper fraction

Mathematics
1 answer:
marusya05 [52]3 years ago
3 0

Answer:

37/5

Step-by-step explanation:

7 2/5 = 37/5

5x7=35

35+2=37

Multiply the whole number and denominator then, add the numerator and put the sum of that back ontop of the denominator

Example:

W N/D   DxW=X  X+N= Y  

W N/D = Y/D

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Solve the following quadratic equations by any method. The solutions are:
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Answer:

Option C .

Step-by-step explanation:

We would like to solve the below <u>quadratic </u><u>equation</u><u> </u>,

\longrightarrow f(x) = x^2-12x +32

Step 1 : <u>E</u><u>q</u><u>u</u><u>a</u><u>t</u><u>e</u><u> </u><u>f</u><u>(</u><u>x</u><u>)</u><u> </u><u>w</u><u>i</u><u>t</u><u>h</u><u> </u><u>0</u><u> </u><u>:</u><u>-</u>

\longrightarrow f(x) = 0\\

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Step 2 : <u>F</u><u>a</u><u>c</u><u>t</u><u>o</u><u>r</u><u>i</u><u>s</u><u>e</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>R</u><u>H</u><u>S</u><u> </u><u>:</u><u>-</u>

\longrightarrow x^2-8x - 4x +32=0\\

\longrightarrow x(x-8)-4(x-8)=0\\

\longrightarrow (x-8)(x-4)=0\\

Step 3 : <u>E</u><u>q</u><u>u</u><u>a</u><u>t</u><u>e</u><u> </u><u>e</u><u>a</u><u>c</u><u>h</u><u> </u><u>f</u><u>a</u><u>c</u><u>t</u><u>o</u><u>r</u><u> </u><u>w</u><u>i</u><u>t</u><u>h</u><u> </u><u>0</u><u> </u><u>:</u><u>-</u>

\longrightarrow x - 8 = 0\\ \qquad x -4=0

\longrightarrow x = 8 \qquad x = 4

\longrightarrow \underline{\underline{\boldsymbol{ x = 8,4}}}

<u>H</u><u>e</u><u>n</u><u>c</u><u>e</u><u> </u><u>o</u><u>p</u><u>t</u><u>i</u><u>o</u><u>n</u><u> </u><u>C</u><u> </u><u>i</u><u>s</u><u> </u><u>c</u><u>o</u><u>r</u><u>r</u><u>e</u><u>c</u><u>t</u><u> </u><u>.</u>

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Answer:

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Step-by-step explanation:

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3 years ago
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To complete this component you will need to insert parentheses in Expression 2 to change the order of operations so the expressi
Alika [10]

Given:

The expression is 5+4\times 2+6-2\times 2-1.

To find:

The position of parentheses inserted in the expression to get the value 19

Step-by-step explanation:

We have,

5+4\times 2+6-2\times 2-1

Now,

(5+4)\times 2+6-2\times 2-1=9\times 2+6-4-1

(5+4)\times 2+6-2\times 2-1=18+6-5

(5+4)\times 2+6-2\times 2-1=18+1

(5+4)\times 2+6-2\times 2-1=19

There are more ways to apply the parenthesis, but we do not get 19.

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5+4*2+\left(6-2\right)*2-1=20\neq 19

5+4*2+6-2*\left(2-1\right)=17\neq 19

And many more possibilities.

Therefore, the expression after inserting the parentheses is (5+4)\times 2+6-2\times 2-1.

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Answer:

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Step-by-step explanation:

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