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Zinaida [17]
3 years ago
10

How to convert 7 2/5 into a improper fraction

Mathematics
1 answer:
marusya05 [52]3 years ago
3 0

Answer:

37/5

Step-by-step explanation:

7 2/5 = 37/5

5x7=35

35+2=37

Multiply the whole number and denominator then, add the numerator and put the sum of that back ontop of the denominator

Example:

W N/D   DxW=X  X+N= Y  

W N/D = Y/D

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What is the answer for 14x divided by 7x
Neporo4naja [7]

Answer:

2x

Step-by-step explanation:

You're dividing 14 multiplied by a number by 7 multiplied by a number. So you'd get 2 multiplied by a number.

8 0
3 years ago
The sum of two prime numbers
Anna35 [415]
The sum of the two prime numbers is 85. This is an odd number. According to the Rule, the sum of the even prime number and the odd prime number is called an odd number.
6 0
3 years ago
Add<br>(4-4i)+(3-2i)<br>Write as complex number in standard form​
Viefleur [7K]

Answer: (4-4i)+(3-2i) = 7-6i

Step-by-step explanation:

To add or subtract two complex numbers, just add or subtract the corresponding real and imaginary parts. For instance, the sum of 4 -4i and 3 - 2i is 7 -6i. The numbers in standard form will be a + bi, where a is the real part and bi is the imaginary part.

8 0
3 years ago
Pls help i need help ASappp
Harrizon [31]
A=πr2=π·92≈254.469
your answer is 254.469
4 0
2 years ago
Read 2 more answers
Write the equation of the sphere in standard form. x^2 + y^2 + z^2 + 2x − 4y − 6z = 22
madam [21]

The equation x^{2} +y^{2} +z^{2} +2x-4y-6z=22  in standard form looks like (x+1)^{2} +(y-2)^{2} +(z-3)^{2} =(6)^{2}.

Given equation of sphere be x^{2} +y^{2} +z^{2} +2x-4y-6z=22.

We are required to express the given equation in the standard form of the equation of sphere.

Equation is basically relationship between two or more variables that are expressed in equal to form. Equation of two variables look like ax+by=c. It may be linear equation,quadratic equation, cubic equation or many more depending on the powers of variables. The standard form of the equation of sphere looks like  x^{2} +y^{2} +z^{2} =r^{2}.

The given equation is x^{2} +y^{2} +z^{2} +2x-4y-6z=22.

We have to break 22 which is in right side into various parts according to the left side of the equation.

x^{2} +y^{2} +z^{2} +2x-4y-6z=-1-4-9+36

x^{2} +y^{2} +z^{2} +2x-4y-6z+1+4+9=36

x^{2} +1+2x+y^{2}+4-4y+z^{2} +9-6z=36

x^{2} +(1)^{2} +2*1*x+y^{2} +(2)^{2} -2*2y+z^{2} +(3)^{2} -2*3z=36

(x+1)^{2} +(y-2)^{2} +(z-3)^{2} =(6)^{2}

Hence the equation x^{2} +y^{2} +z^{2} +2x-4y-6z=22  in standard form looks like (x+1)^{2} +(y-2)^{2} +(z-3)^{2} =(6)^{2}.

Learn more about equations at brainly.com/question/2972832

#SPJ4

7 0
1 year ago
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