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lianna [129]
3 years ago
12

Your answer is incorrect.

Mathematics
1 answer:
ahrayia [7]3 years ago
5 0

Answer:

x² + y² = 25

Step-by-step explanation:

(x - h)² + (y - k)² = r²

Centre: origin --> (0,0)

r² = (-5-0)² + (0 - 0)² = 25

x² + y² = 25

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The school cafeteria sells two types of wraps vegetarian and chicken the vegetarian wrap costs $1.00 and the chicken wrap costs
IRINA_888 [86]

Answer:

35

Step-by-step explanation:

Let's make a system of equations for the vegetarian and chicken wraps; one for the total cost of them and one for the total amount sold.

Vegetarian wraps will be represented by variable v and chicken wraps will be represented by the variable c.

  • v + 3.40c = 266.20
  • v + c = 103

Subtract these equations.

  • 2.40c = 163.20

Divide both sides by 2.40.

  • c = 68

Substitute this value for c into the second equation.

  • v + (68) = 103

Subtract 68 from both sides.

  • v = 35  

The number of vegetarian wraps sold amounted to 35 in total.

3 0
3 years ago
Read 2 more answers
I could use some help!!
12345 [234]

Answer:

84

Step-by-step explanation:

The interquartile range is obtained using the relation :

Third quartile (Q3). - First quartile (Q1)

From. The boxplot :

Q3 = 96

Q1 = 12

Interquartile range (IQR) = Q3 - Q1 = 96 - 12 = 84

6 0
3 years ago
Vanessa uses the expressions (3x² + 5x + 10) and (x² – 3x - 1) to represent the length and width of her patio.
Kay [80]

Answer:

a) 3x⁴-4x³-8x²-35x-10

Step-by-step explanation:

3x2(x²-3x-1)+5x(x²-3x-1)+10(x²-3x-1)

3x⁴-9x³-3x²+5x³-15x²-5x+10x²-30x-10

3x⁴-9x³+5x³-3x²-15x²+10x²-5x-30x-10

3x⁴-4x³-8x²-35x-10

5 0
2 years ago
Hamish rides his bike at an average speed of 22 km/h. How far does he ride in:
Andrej [43]
1=55 km
2=16.5km
3=5.5km
5 0
3 years ago
Read 2 more answers
You borrow $5,000 from your parents to purchase a used car. The arrangements of the loan are such that you make payments of $250
AfilCa [17]
Part A:
1st month: Interest payable = 1% of $5,000 = $50.00
Amount paid in first month = $250 + $50.00 = $300
Unpaid balance = $5,000 - $250 = $4,750

2nd month: Interest payable = 1% of $4,750 = $47.50
Amount paid in second month = $250 + $47.50 = $297.50
Unpaid balance = $4,750 - $250 = $4,500

3rd month: Interest payable = 1% of $4,500 = $45.00
Amount paid in third month = $250 + $45.00 = $295.00
Unpaid balance = $4,500 - $250 = $4,250

4th month: Interest payable = 1% of $4,250 = $42.50
Amount paid in fouth month = $250 + $42.50 = $292.50
Unpaid balance = $4,250 - $250 = $4,000

5th month: Interest payable = 1% of $4,000 = $40.00
Amount paid in fifth month = $250 + $40.00 = $290.00
Unpaid balance = $4,000 - $250 = $3,750

6th month: Interest payable = 1% of $3,750 = $37.50
Amount paid in sixth month = $250 + $37.50 = $287.50
Unpaid balance = $3,750 - $250 = $3,500

7th month: Interest payable = 1% of $3,500 = $35.00
Amount paid in seventh month = $250 + $35.00 = $285.00
Unpaid balance = $3,500 - $250 = $3,250

8th month: Interest payable = 1% of $3,250 = $32.50
Amount paid in eighth month = $250 + $32.50 = $282.50
Unpaid balance = $3,250 - $250 = $3,000

9th month: Interest payable = 1% of $3,000 = $30.00
Amount paid in ninth month = $250 + $30.00 = $280.00
Unpaid balance = $3,000 - $250 = $2,750

10th month: Interest payable = 1% of $2,750 = $27.50
Amount paid in fouth month = $250 + $27.50 = $277.50
Unpaid balance = $2,750 - $250 = $2,500

11th month: Interest payable = 1% of $2,500 = $25.00
Amount paid in seventh month = $250 + $25.00 = $275.00
Unpaid balance = $2,500 - $250 = $2,250

12th month: Interest payable = 1% of $2,250 = $22.50
Amount paid in eighth month = $250 + $22.50 = $272.50
Unpaid balance = $2,250 - $250 = $2,000



Part B:
Number of payments = 5000 / 250 = 20
Total amount of interest = 50 + 47.5 + 45 + . . . + upto the 20th payment.
This is an arithmetic sequence with the first term as 50, common difference as -2.5 and number of terms = 20.

Sum of the first 20th term of the GP is given by
S_n= \frac{20}{2}[2(50)+(20-1)(-2.5)] \\  \\ =10(100-2.5(19))=10(100-47.5) \\  \\ =10(52.5)=\$525.00

Therefore, the <span>total amount of interest paid over the term of the loan is $525.00</span>
8 0
3 years ago
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