Answer:
m∠4 = 55°
Step-by-step explanation:
From the figure attached,
m∠DBC = m∠BCA + m∠BAC [Exterior angle of a triangle equals the sum of the remote interior angles]
m∠4 = 30° + 25° = 55°
Therefore, m∠4 = 55° will be the answer.
The magnitude of the tension on the ends of the clothesline is mathematically given as
T= 47.6194N
<h3>What is the magnitude of the tension on the ends of the clothesline?</h3>
Generally, the equation for AB^2 is mathematically given as
AB² = AQ² +BQ²
Therefore
AB²=5²+32
AB² = 25+9
AB² = 34
AB=√34
sin ∅ = ав AB
Sin∅ = 3 √34
Let T1 and T₂ be tension in AB and BC respectively
The horizontal component of tension. T1 cos∅ = T₂cos ∅
T₁ = T₂
The vertical component of tension
T1 sin∅. + T₂ sin ∅ = mg
Tsin∅+ Tsin∅ = mg
T = mg/2sin∅
T=5*9.82/ 2 sin ∅
T= 47.6194N
In conclusion, the magnitude of the tension
T= 47.6194N
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The pythagorean theorem talks about the 3 sides of a right triangle
the 2 legs, a and b and the hypotenuse c.
a^2 + b^2 = c^2