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strojnjashka [21]
3 years ago
12

Chemistry Lab Question: Filtration

Chemistry
1 answer:
tatyana61 [14]3 years ago
6 0

For the first question, salt is soluble while sand is insoluble or not dissolvable in water. The salt should have vanished or melted, but the sand stayed noticeable or visible, making a dark brown solution probably with some sand particles caught on the walls of the container when the boiling water was put in to the mixture of salt and sand. The solubility of a chemical can be disturbed by temperature, and in the case of salt in water, the hot temperature of the boiling water enhanced the salt's capability to melt in it.

For the second question, the melted or dissolved salt should have easily made its way through the filter paper and into the second container, while the undissolved and muddy sand particles is caught on the filter paper. The size of the pores of the filter paper didn’t change. On the contrary, the size of the salt became smaller because it has been dissolved which is also the reason why it was able to go through the filter paper, while the size of the sand may have doubled or even tripled which made it harder to pass through.

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Some velomobile seats have been designed to hold ice packs inside their cushions. If you started a ride with ice packs that held
Cerrena [4.2K]

Answer : The heat energy absorbed will be, 1.23\times 10^5cal

Solution :

The process involved in this problem are :

(1):H_2O(s)(0^oC)\rightarrow H_2O(l)(0^oC)\\\\(2):H_2O(l)(0^oC)\rightarrow H_2O(l)(32.0^oC)

The expression used will be:

\Delta H=m\times \Delta H_{fusion}+[m\times c_{p,l}\times (T_{final}-T_{initial})]

where,

m = mass of ice = 1100 g

c_{p,l} = specific heat of liquid water = 4.18J/g^oC

\Delta H_{fusion} = enthalpy change for fusion = 6.01kJ/mole=6010J/mole=\frac{6010J/mole}{18g/mole}J/g=333.89J/g

Molar mass of water = 18 g/mole

Now put all the given values in the above expression, we get:

\Delta H=1100g\times 333.89J/g+[1100g\times 4.18J/g^oC\times (32.0-0)^oC]

\Delta H=514415J=122948.1358cal=1.23\times 10^5cal

Conversion used : (1 cal = 4.184 J)

Therefore, the heat energy absorbed will be, 1.23\times 10^5cal

7 0
3 years ago
Which has the highest viscory ? Milk ? Water ? Orange juice?
Snezhnost [94]
I guess you mean viscosity
Anyhow the answer is milk
5 0
2 years ago
1. ¿Cuál de los factores se deben emplear para convertir: a. ¿Número de moles de cloro en número de moles de NaCl? b. Moles de s
Alex

Answer:

Número de moles de cloro en número de moles de NaCl

Explanation:

espero que si sea la correcta

7 0
2 years ago
What is the wavelength in nm of a light whose first order bright band forms a
miskamm [114]

Answer:

714 nm

Explanation:

Using the equation: nλ=d<em>sin</em>θ

where

n= order of maximum

λ= wavelength

d= distance between lines on diffraction grating

θ= angle

n is 1 because the problem states the light forms 1st order bright band

λ is unknown

d=  \frac{1}{700,000} or 0.0000014 (meters)

sin(30)= 0.5

so

(1)λ=(0.0000014)(0.5)

=0.000000714m or 714 nm

3 0
2 years ago
Jesse travels 3.0 meters east and then turns and travels 4.0 meters north. What distance did Jesse travel? 1 m 5 m, northeast 7
boyakko [2]
7.0 meters because 3.0+4.0=7 
3 0
3 years ago
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