Depends on what compound we’re talking about here
Answer:
A solution labeled "0.105 M NaOH" would contain 0.105 moles of NaOH in each liter of solution.
Explanation:
The concentration of a solution in Molarity (M) stands for the number of moles of that substance contained in 1 L of solution.
Molarity = Concentration in mol/L = (Number of moles of solute) ÷ (Volume of solution in L)
Molarity = Concentration in mol/L = 0.105 M = 0.105 mol/L
Number of moles of solute = ?
Volume of solution in L = 1 L
0.105 = Number of moles of solute × 1
Number of moles of solute = 0.105 mole
Hence, a solution labeled "0.105 M NaOH" would contain 0.105 moles of NaOH in each liter of solution.
Hope this Helps!!!
Plants
do. Good luck with whatever you are doing :)
Answer:
- <u><em>The leftover reactant is the nitrogen gas, N₂.</em></u>
Explanation:
As per your description:
<u>1. Square on the left: N₂(g)</u>
- 3 units of two joint circles: this represents 3 molecules of nitrogen gas, N₂(g).
<u>2. Square on the right: H₂(g)</u>
- 3 units of two joint circles: this represents 3 molecules of hydrogen gas, H₂(g).
<u>3. Reaction</u>
If the maximum possible amount of NH₃ is formed during the reaction, you assume that the reaction goes to completion.
The chemical equation that represents the reaction is:
Which must be balanced:
That means that 1 molecule (or 1 mol) of N₂(g) reacts with 3 molecules (or 3 moles ) of H₂(g) to produce 2 molecules (or 2 moles) of NH₃(g).
Since, the squares show that there are 3 molecules of each reactant, the 3 molecules of hydrogen gas will be able to react with 1 molecule of nitrogen gas. When that happens, all the hydrogen gas is consumend and yet two molecules of nitrogen gas will remain unreacted. Hence, the nitrogen gas is the leftover reactant.
