I believe that the answer would be true
C because we need materials in the lab
The average distance a gas particle travels between collisions (with the wall or another particle is called the mean free path.
According to the kinetic theory of gases, the particles of a gas (atoms or molecules) have the highest kinetic energy and travel at high speeds. At standard temperature and pressure, a gas particle can reach speeds of about 470m/s.
Despite the high speeds gas particles travel, it still takes a while for the fragrance of an opened perfume to diffuse to the other end of the room. This is because when moving, the molecules do not have a free path. They constantly collide with other particles and the walls of the container and change direction randomly. The average distance a single particle can travel without colliding with other particles, or the wall of the container is called the mean free path.
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Answer:
2,347.8 grams
Explanation:
The freezing point depression Kf of water = 1.86° C / molal.
To still freeze at -12° C, then the molality of the solution 12/ 1.86 = 6.45 moles
The molecular weight of sorbitol (C6H14O6)is:
6 C = 6 ×12 = 72
14 H = 14 × 1 = 14
6 O = 6 × 16 = 96
...giving a total of 182
So one mole of sorbitol has a mass of 182 grams.
Since there are 2 kg of water, 2 × 6.45 moles = 12.9 moles can be added to the water to get the 12° C freezing point depression.
Therefore
grams = moles × molar mass
12.9 moles × 182 grams / mole = 2,347.8 grams of sorbitol can be added and still freeze
Answer:
The molar mass and atomic mass are essentially the same for an element
Explanation:
The molar mass of a substance can be obtained by dividing the mass of the substance by the no of moles of the substance present.
The atomic mass of an element is the number of protons and neutrons present in the substance.
These two measurements usually give the same values because they both make reference to the 1/12th the mass of carbon-12 for their measurement.
Because they both have the same reference point, though they have different calculating procedures, the results obtained will be similar.
