Answer:
1st case; mass=40 kg
v=25m/s
K.E.=1/2[40][25]^2=12,500 J
2nd case; mass=4,000 kg
v=2 m/s
K.E.=1/2[4000][2]^2=8000J
in case 1 Kinetic energy is greater.
Explanation:
Answer:
P = 23.32 W
Explanation:
In series
equivalent Resistance
R(eq)=R+R=2R
In parallel equivalent resistance
R(eq) = R*R/(R+R) =R/2
since.
power
P=V² / R
in series
⇒V = √(P*R)
=√(5.83*2R
)
=√(11.66R)
in parallel
P = V² / R(eq)
=(√(11.66R)²) / (R/2)
P=11.66 * R * 2/R
P = 23.32 W
Find the angles which the vecotr <span><span><span><span><span>v </span><span>⃗ </span></span>=3i−6j+2k</span> </span><span><span>v→</span>=3i−6j+2k</span></span>
makes with the coordinate axes.
If the angles are <span><span><span>α,β,θ</span> </span><span>α,β,θ</span></span>
, show that for any 3-dimensional vector:
. . . <span><span><span><span><span>cos </span><span>2 </span></span>α+co<span><span>s </span><span>2 </span></span>β+<span><span>cos </span><span>2 </span></span>θ=1</span> </span><span><span>cos2</span>α+co<span>s2</span>β+<span>cos2</span>θ=1</span></span>
Answer:
Upward direction.
The friction is kinetic friction