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Zinaida [17]
3 years ago
7

Please help me, I'm not good in physics.

Physics
1 answer:
expeople1 [14]3 years ago
3 0

Answer:

Upward direction.

The friction is kinetic friction

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A 3.5 kW drill transfers 5 000 kJ of kinetic energy during 15 seconds of use. What is the percentage efficiency of the drill?
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Answer:

1.04%

Explanation:

Given that,

The power of drill = 3.5 kW = 3500 W

Transferred kinetic energy = 5000 kJ during 15 seconds of use.

We need to find the percentage efficiency of the drill. It can be given by :

\eta=\dfrac{P_o}{P_i}\times 100

Where

Po and Pi are output and input powers.

P_o=\dfrac{5000\times 10^3}{15}\\\\=3.34\times 10^5\ W

So,

\eta=\dfrac{3500}{3.34\times10^{5}}\times100\\\\=1.04\%

So, the percentage efficiency of the drill is 1.04%.

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A charge q of 1.3 × 10-16 coulombs moves from point A to a lower potential at point B in an electric field of 3.2 × 102 newtons/
LUCKY_DIMON [66]

Explanation :

It is given that,

Charge, q=1.3\times 10^{-16}\ C

Electric field, E=3.2\times 10^2\ N/C

Distance, d=1.1\times 10^{-2}\ m

The work done is stored in the form of potential energy.

W=F.d

\because F=qE

So, W=qE\ d

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W=4.576\times 10^{-16}\ J

Hence, this is the required solution.

5 0
3 years ago
Read 2 more answers
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