Answer:
L= 1 m, ΔL = 0.0074 m
Explanation:
A clock is a simple pendulum with angular velocity
w = √ g / L
Angular velocity is related to frequency and period.
w = 2π f = 2π / T
We replace
2π / T = √ g / L
T = 2π √L / g
We will use the value of g = 9.8 m / s², the initial length of the pendulum, in general it is 1 m (L = 1m)
With this length the average time period is
T = 2π √1 / 9.8
T = 2.0 s
They indicate that the error accumulated in a day is 15 s, let's use a rule of proportions to find the error is a swing
t = 1 day (24h / 1day) (3600s / 1h) = 86400 s
e= Δt = 15 (2/86400) = 3.5 104 s
The time the clock measures is
T ’= To - e
T’= 2.0 -0.00035
T’= 1.99965 s
Let's look for the length of the pendulum to challenge time (t ’)
L’= T’² g / 4π²
L’= 1.99965 2 9.8 / 4π²
L ’= 0.9926 m
Therefore the amount that should adjust the length is
ΔL = L - L’
ΔL = 1.00 - 0.9926
ΔL = 0.0074 m
Answer:
S = 2 * pi * 1 m = 6.28 m = distance traveled
V = S / T or T = S / V = 6.28 m / 5 m/s = 1.26 sec
This will be the time for 1 revolution or the period of the motion.
Answer:
figure one (step up transformer) helps in increasing the output voltage
figure two (step down transformer) helps in decreasing the output voltage
First:
d = 100 m
t = 200 sec
v = 100/200 = 0.5 m/s
Displacement is zero since he returned to his start point.
t2 = d/v2 = 100/2 = 50 sec
total time = 50 + 200 + 500 = 750 sec
Answer:
For any collision occurring in an isolated system, momentum is conserved. The total amount of momentum of the collection of objects in the system is the same before the collision as after the collision.
Explanation:
Hope this helps
