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2 years ago

What value of x makes the equation true?

Mathematics

2 answers:

Gekata [30.6K]2 years ago

5 0

Any answer choices? BUT if your SOLVING for x then x=5

kramer2 years ago

4 0

Answer: The required value of x for which the given equation is true is 5.

Step-by-step explanation: We are given to find the value of x for which the following equation is true :

$\dfrac{1}{2}(4x-5)+\dfrac{5}{2}=10~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

To find the value of x, we need to solve the given equation.

The solution of equation (i) is as follows :

$\dfrac{1}{2}(4x-5)+\dfrac{5}{2}=10\\\\\\\Rightarrow \dfrac{4x-5+5}{2}=10\\\\\\\Rightarrow \dfrac{4x}{2}=10\\\\\\\Rightarrow 2x=10\\\\\\\Rightarrow x=\dfrac{10}{2}\\\\\Rightarrow x=5.$

Thus, the required value of x for which the given equation is true is 5.

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Seller Andy require a 2.5% deposit on all offers. Buyer josh wants to offer $452,000 for the property. The property was appraise

arlik [135]

Answer: $11,300

Step-by-step explanation:

Given the following :

Buyer Josh's offering price = $452,000

Required deposit rate = 2.5%

Earnest money deposit is the product of :

Offering price × required deposit accepted

$452,000 × 2.5%

$452,000 × 0.025 = $11,300

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2 years ago

If 6/9 is equal to 10/R, what is R?

sladkih [1.3K]

Answer:

r = 15

Step-by-step explanation:

I don't really have an explanation, I'm just good at quick math,

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2 years ago

Choose all the answers that apply. Todd drops three balls made of different materials to see how high they will bounce. He drops

iragen [17]

The independent variable is the type of material the balls are made from

6 0

2 years ago

Simplify (0.5)2+3.5divided by 5

patriot [66]

Answer:

2.7

Step-by-step explanation:

7 0

2 years ago

Please help solve for x..

aalyn [17]

Answer:

x = 1 or x = -1

Step-by-step explanation:

Given equation:

$x^{100}-4^x \cdot x^{98}-x^2+4^x=0$

Factor out -1:

$\implies -1(-x^{100}+4^x \cdot x^{98}+x^2-4^x)=0$

Divide both sides by -1:

$\implies -x^{100}+4^x \cdot x^{98}+x^2-4^x=0$

Rearrange the terms:

$\implies 4^x \cdot x^{98}-4^x-x^{100}+x^2=0$

$\textsf{Apply exponent rule} \quad a^{b+c}=a^b \cdot a^c \quad \textsf{to }x^{100}:$

$\implies 4^x \cdot x^{98}-4^x-x^{98}x^2+x^2=0$

Factor the first two terms and the last two terms separately:

$\implies 4^x(x^{98}-1)-x^2(x^{98}-1)=0$

Factor out the common term $(x^{98}-1)$ :

$\implies (4^x-x^2)(x^{98}-1)=0$

Zero Product Property: If a ⋅ b = 0 then either a = 0 or b = 0 (or both).

Using the Zero Product Property, set each factor equal to zero and solve for x (if possible):

$\begin{aligned}x^{98}-1 & = 0 & \quad \textsf{or} \quad \quad4^x-x^2 & = 0 \\x^{98} & =1 & 4^x & = x^2 \\x & = 1, -1 & \textsf{no}& \textsf{ solutions for } x \in \mathbb{R}\end{aligned}$

Therefore, the solutions to the given equation are: x = 1 or x = -1

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3 0

1 year ago