All categories

1 year ago

Find the x- and y-

Mathematics

1 answer:

Galina-37 [17]1 year ago

5 0

Answer:

(-3/4, 0) and (0, 3/2)

Step-by-step explanation:

The $x$ -intercept is when $y=0$ .

$\frac{3}{4}+x=0 \implies x=-3/4$

So, the $x$ intercept has coordinates $(-3/4, 0)$ .

The $y$ intercept is when $x=0$ .

$\frac{3}{4}=\frac{1}{2}y \implies y=3/2$ .

So, the $y$ intercept has coordinates $(0, 3/2)$

You might be interested in

What’s negative 9 and 2 sevenths subtracted by negative 10 and three sevenths

Nutka1998 [239]

Answer:

8 over 7

Step-by-step explanation:

Convert the mixed numbers to improper fractions, then find the LCD and combine.

Glad I could help!!

8 0

3 years ago

Read 2 more answers

What is the slope of the line shown in the graph below?

Flauer [41]

Slope = (y2-y1)/(x2-x1)
The points: (2,0) and (0,3)
(3-0)/(0-2) = 3/-2 = -3/2
The solution is -3/2

4 0

2 years ago

Read 2 more answers

Two equal groups of seedlings, and equal in height, were selected for an experiment. One group of seedlings was fed Fertilizer A

ser-zykov [4K]

Answer:

Null Hypothesis: H_0: \mu_A =\mu _B or \mu_A -\mu _B=0

Alternate Hypothesis: H_1: \mu_A >\mu _B or \mu_A -\mu _B>0

Here to test Fertilizer A height is greater than Fertilizer B

Two Sample T Test:

t=\frac{X_1-X_2}{\sqrt{S_p^2(1/n_1+1/n_2)}}

Where S_p^2=\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2}

S_p^2=\frac{(14)0.25^2+(12)0.2^2}{15+13-2}= 0.0521154

t=\frac{12.92-12.63}{\sqrt{0.0521154(1/15+1/13)}}= 3.3524

P value for Test Statistic of P(3.3524,26) = 0.0012

df = n1+n2-2 = 26

Critical value of P : t_{0.025,26}=2.05553

We can conclude that Test statistic is significant. Sufficient evidence to prove that we can Reject Null hypothesis and can say Fertilizer A is greater than Fertilizer B.

6 0

2 years ago

What is (-6) to the negative 5 exponent over 3 to the negative 2 exponent?

loris [4]

Answer:

$\displaystyle -\frac{1}{864}$

Step-by-step explanation:

$\displaystyle \frac{-6^{-5}}{3^{-2}} = \frac{-\frac{1}{7776}}{\frac{1}{9}} = -\frac{1}{864}$

8 0

3 years ago

Assuming that the heights of college women are normally distributed with mean 64 inches and standard deviation 1.5 inches, what

professor190 [17]

Answer:

15.74% of women are between 65.5 inches and 68.5 inches.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 64, \sigma = 1.5$