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Aleksandr [31]
1 year ago
14

Find the x- and y-

Mathematics
1 answer:
Galina-37 [17]1 year ago
5 0

Answer:

(-3/4, 0) and (0, 3/2)

Step-by-step explanation:

The x-intercept is when y=0.

\frac{3}{4}+x=0 \implies x=-3/4

So, the x intercept has coordinates (-3/4, 0).

The y intercept is when x=0.

\frac{3}{4}=\frac{1}{2}y \implies y=3/2.

So, the y intercept has coordinates (0, 3/2)

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Yo solve....14√x+15 = 71
user100 [1]

Answer:

plug in 16 for x

14√x+15 = 71

14√x+15-15 = 71-15 = 56

14√x/14 = 56/14 = 4

√x^2 = 4^2 = 16

7 0
3 years ago
What is the range of function y=√(-2cos^2x+3cosx-1)
Ugo [173]
Hello Friend,here is the solution for your question


<span>so the given function is </span>
y= √(-2cos²x+3cosx-1)
 i.e = √[-2(cos²x-3/2+1/2)]
i.e = √[-2(cosx-3/4)²-9/16+1/2]
i.e. = √[-2(cos-3/4)²-1/16]
i.e. = √[1/8-3(cosx=3/4)²]-----------(1)

Now here  in this equation is this quantity :-
<span>(cosx=3/4)²----------------(2)   is to it's minimum value then the whole equation </span>
<span>i.e. = √[1/8-3(cosx=3/4)²] will be maximum and vice versa </span>


And we know that cosx-3/4 will be minimum if cosx=3/4
<span>therefore put this in (1) we get </span>
(cosx=3/4)²=0    [ cosx=3/4]
<span>hence the minimum value of the quantity (cosx=3/4)² is 0 </span>

<span>put this in equation (1) </span>
we get ,
i.e. = √[1/8-3(cosx=3/4)²]
   =√[1/8-3(0)]        [ because minimum value of of the quantity (cosx=3/4)² is 0 ]
     =√1/8
      =1/(2√2)

<span>this is the maximum value now to find the minimum value </span>

<span>since this is function of root so the value of y will always be ≥0 </span>

<span>hence the minimum value of the function y is 0 </span>


<span>Therefore, the range of function </span>y is [0,1/(2√2)]


__Well,I have explained explained each and every step,do tell me if you don't understand any step._

8 0
3 years ago
Please help me .!<br> 10 points .!
BaLLatris [955]
The answer is 19 I subtracted the 2 biggest numbers
5 0
3 years ago
10 points! What is the slope of the given line?
aleksklad [387]

Answer:

-5/2

Step-by-step explanation:

8 0
3 years ago
If f(x) =1/x and g(x) = x - 2 what is f(g(x)) when X = 1​
Fed [463]

Answer:

f(g(x)) = -1

Step-by-step explanation:

f(x) =  \frac{1}{x}  \\  \\ g(x) = x - 2 \\  \\  \implies \: f(g(x)) =  \frac{1}{x - 2}  \\  \\  \implies \: f(g(1)) =  \frac{1}{1 - 2} \\  \\  \implies \: f(g(1)) =  \frac{1}{ - 1} \\  \\  \implies \: f(g(1)) =   - 1

8 0
2 years ago
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