Question

Given g(x) = 5x^-4- 3xº, find g(-2). Show all intermediate steps. Write answer as a fraction in lowest

Answer 1

Answer:

g(- 2) = - $\frac{43}{16}$

Step-by-step explanation:

Using the rules of exponents

$a^{-m}$ = $\frac{1}{a^{m} }$ and $a^{0}$ = 1

Given

g(x) = 5$x^{-4}$ - 3$x^{0}$, then

g(- 2) = 5$(-2)^{-4}$ - 3$(-2)^{0}$ = $\frac{5}{(-2)^{4} }$ - 3(1) = $\frac{5}{16}$ - $\frac{48}{16}$ = - $\frac{43}{16}$