I use the sin rule to find the area
A=(1/2)a*b*sin(∡ab)
1) A=(1/2)*(AB)*(BC)*sin(∡B)
sin(∡B)=[2*A]/[(AB)*(BC)]
we know that
A=5√3
BC=4
AB=5
then
sin(∡B)=[2*5√3]/[(5)*(4)]=10√3/20=√3/2
(∡B)=arc sin (√3/2)= 60°
now i use the the Law of Cosines
c2 = a2 + b2 − 2ab cos(C)
AC²=AB²+BC²-2AB*BC*cos (∡B)
AC²=5²+4²-2*(5)*(4)*cos (60)----------- > 25+16-40*(1/2)=21
AC=√21= 4.58 cms
the answer part 1) is 4.58 cms
2) we know that
a/sinA=b/sin B=c/sinC
and
∡K=α
∡M=β
ME=b
then
b/sin(α)=KE/sin(β)=KM/sin(180-(α+β))
KE=b*sin(β)/sin(α)
A=(1/2)*(ME)*(KE)*sin(180-(α+β))
sin(180-(α+β))=sin(α+β)
A=(1/2)*(b)*(b*sin(β)/sin(α))*sin(α+β)=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)
A=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)
KE/sin(β)=KM/sin(180-(α+β))
KM=(KE/sin(β))*sin(180-(α+β))--------- > KM=(KE/sin(β))*sin(α+β)
the answers part 2) areside KE=b*sin(β)/sin(α)side KM=(KE/sin(β))*sin(α+β)Area A=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)
Answer:
E
Step-by-step explanation:
There are both red and green marbles in the jar. The answer cannot be A or D because that would mean that there's 1.14% or 1.04% green marbles. But we know that there's less than that in the and bag. And there are also red marbles. B and F do not work because there can't be a negative amount of marbles in the bag.
Answer:
Hannah is deciding between two truck rental companies. Company A charges an initial fee of $30 for the rental plus $2 per mile driven. Company B charges an initial fee of $100 for the rental plus $1 per mile driven. Let AA represent the amount Company A would charge if Hannah drives xx miles, and let BB represent the amount Company B would charge if Hannah drives xx miles. Write an equation for each situation, in terms of x,x, and determine the interval of miles driven, x,x, for which Company A is cheaper than Company B.
Answer:
r = - 13 / 15 inches/week
Step-by-step explanation:
The numerator is 13
and the denominator is 15, then we have
r = - 13 / 15 inches/week
r < 0 since the water level of the lake fell
