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NeTakaya
3 years ago
11

I NEED EMERGENCY SOS

Mathematics
1 answer:
maks197457 [2]3 years ago
6 0

Answer:

12

Step-by-step explanation:

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Which equation, when graphed, has x-intercepts at (2, 0) and (4, 0) and a y-intercept of (0, â€"16)? f(x) = â€"(x â€" 2)(x â€" 4
zmey [24]

To find the equation, for the x-intercepts at (2, 0) and (4, 0) and a y-intercept of (0, –16) we have to find the nature of the curve.

The correct option is f(x) = –2(x – 2)(x – 4).

Given:

The x-intercepts at (2, 0) and (4, 0).

The y-intercept of (0, –16).

The nature of the graph is quadratic curve. Write the general equation for x-intercept.

y=a(x-2)(x-4)

Where is a number

Substitute 0 for x.

y=a(0-2)(-4)\\y=8a

We have y-intercept of (0, –16).

-16=8a\\a=-2

The equation would be,

f(x) = -2(x - 2)(x - 4).

Thus, the correct option is f(x) = –2(x – 2)(x – 4).

Learn more about equitation here:

brainly.com/question/3337307

3 0
3 years ago
Divide the following polynomial, then place the answer in the proper location on the grid. (9x 4 + 3x 3y - 5x 2y 2 + xy 3) / (3x
olga55 [171]
The answer is -4+72/2y+9 when you solve using polynomial division :)
3 0
3 years ago
What are the requirements for an experiment to be able to show that changes in one variable cause changes in another?
uranmaximum [27]

ANSWER;

Variables

Variables are factors in an experiment that can change. There are three types of variables in a scientific experiment: independent, dependent and controlled variables. The scientist changes the independent variable in a systematic manner and measures the effects of this change on the dependent variable. The other variables are called controlled variables because the experiment is designed to keep them at an unchanging value, known as "controlling" a variable. A valid experiment should have only one independent variable.

6 0
3 years ago
Read 2 more answers
What is 0.482 repeating as a simplified fraction?
weeeeeb [17]

the idea being, we multiply the value by some power of 10 just to move the repeating digits to the left of the decimal point.  We have 3 digits, we'll use 1000, anyhow, without further adieu,


\bf \begin{array}{|ccl|ll}
\cline{1-3}
\stackrel{\qquad}{x=0.\overline{482}}&&\\
\cline{1-3}
&&\\
\stackrel{\textit{3 digits, we use 3 zeros}}{1000\cdot x}&=&482.\overline{482}\\
&&482+0.\overline{482}\\
&&482+x\\
&&\\
\cline{1-3}
\end{array}\implies 1000x=482+x
\\\\\\
999x=482\implies x=\cfrac{482}{999}

4 0
3 years ago
Please help Asap
daser333 [38]
The answer is 8. :).
5 0
3 years ago
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