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3 years ago

10

I need help with this as soon as possible

1 answer:

Arte-miy333 [17]3 years ago

5 0

Yes the graph does show a proportional relationship because each x value has only one y value

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Estimate then find the product of 4 times 979

DochEvi [55]

Estimate first. Estimate is basically the same as saying round, so 979 would be rounded to 1,000. 4 x 1,000 = 4,000. 4,000 is the answer. :)

Thanks for your question! Don't forget to rate and give me the brainliest answer! Then, I can help you with all your problems! ^-^ ~

3 0

3 years ago

Which of these is an optional deduction for money to be taken out of an employee's paycheck?

andreev551 [17]

Answer:

C

Step-by-step explanation:

Federal income tax is a must deduction. The answer is not D

Social Security since FDRs presidency is a must. The answer is not B

Medicare is a must. Since 1966 it is a must Lyndon Johnson brought it in.

The answer is C. It is voluntary.

5 0

4 years ago

A patient ingests 5 grams of a certain drug which

IgorC [24]

Answer:

8 hours

Step-by-step explanation:

5 - 1 = 4 grams

10% of 5 = 0.5 grams per hour

4/0.5 = 8 hours

8 0

3 years ago

Find the unknown side length

7nadin3 [17]

Answer:

length is 6 cm

Step-by-step explanation:

area = 14cm^2

breadth = 7/3 cm

length = area/breadth

length= 14/7/3

14×3/7= 6cm of length

3 0

3 years ago

How do you determine the area under a curve in calculus using integrals or the limit definition of integrals?

RSB [31]

Answer:

Please check the explanation.

Step-by-step explanation:

Let us consider

$y = f(x)$

To find the area under the curve $y = f(x)$ between $x = a$ and $x = b$ , all we need is to integrate $y = f(x)$ between the limits of $a$ and $b$ .

For example, the area between the curve y = x² - 4 and the x-axis on an interval [2, -2] can be calculated as:

$A=\int _a^b|f\left(x\right)|dx$

= $\int _{-2}^2\left|x^2-4\right|dx$

$\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx$

$=\int _{-2}^2x^2dx-\int _{-2}^24dx$

solving

$\int _{-2}^2x^2dx$

$\mathrm{Apply\:the\:Power\:Rule}:\quad \int x^adx=\frac{x^{a+1}}{a+1},\:\quad \:a\ne -1$

$=\left[\frac{x^{2+1}}{2+1}\right]^2_{-2}$

$=\left[\frac{x^3}{3}\right]^2_{-2}$

computing the boundaries

$=\frac{16}{3}$

Thus,

$\int _{-2}^2x^2dx=\frac{16}{3}$

similarly solving

$\int _{-2}^24dx$

$\mathrm{Integral\:of\:a\:constant}:\quad \int adx=ax$

$=\left[4x\right]^2_{-2}$

computing the boundaries

$=16$

Thus,

$\int _{-2}^24dx=16$

Therefore, the expression becomes

$A=\int _a^b|f\left(x\right)|dx=\int _{-2}^2x^2dx-\int _{-2}^24dx$

$=\frac{16}{3}-16$

$=-\frac{32}{3}$

$=-10.67$ square units

Thus, the area under a curve is -10.67 square units

The area is negative because it is below the x-axis. Please check the attached figure.

6 0

3 years ago