All categories

3 years ago

Need help to solve.

Mathematics

1 answer:

vredina [299]3 years ago

5 0

Answer: y-intercept: (0, -0.7) and x-intercept: (-1.2, 0)

Recall: The coordinate of a point is always written as (x,y).

Look to the x- and y-axis and see where there's a point that's exactly on it; that'll be your x- and y-intercept.

The point (0, -0.7) is on the y-axis, so that's your y-intercept. The point (-1.2, 0) is on the x-axis, so that's your x-intercept.

You might be interested in

On a math test, 5 out of 20 students got an A. If three students are chosen at random without replacement, what is the probabili

Y_Kistochka [10]

Answer:

Step-by-step explanation:

7 0

3 years ago

Kim’s hair grows a half inch per month. How many months will it take for her hair to grow 12 inches?

Contact [7]

Answer:

24 months

Step-by-step explanation:

Cross-multiply

0.5 inches -------------- 1 month

12 inches ---------------- x months

0.5/12 = 1/x ===> 0.5x = 12 ===> x = 12/0.5 ===> x = 24 months

3 0

3 years ago

Write the inequality that represents the sentence, "Six less than a number is greater than 53."

Fiesta28 [93]

Answer:

6<x>53

Step-by-step explanation:

x = number

6 is less than = 6<

greater than 53 = >53

put it all together

6<x>53

4 0

3 years ago

How find a ratio of the area of a circle and a square

ladessa [460]

Answer:

CIRCLE : CIRCLE

Ratio of area is the scale factor squared. So find the radii of the two circles, square both values, and simplify the ratio.

SQUARE : SQUARE

Ratio of area is the scale factor squared, So find the side lengths of the two squares, square both values, and simplify the ratio.

SQUARE : CIRCLE

Using the formulas A = s*s and A = pi*r^2, find the areas of the circle and the square. Then simplify the ratio.

5 0

2 years ago

(1 point) consider the function f(t)=⎧⎩⎨⎪⎪⎪⎪0,−5,−6,6,t<00≤t<11≤t<7t≥7;f(t)={0,t<0−5,0≤t<1−6,1≤t<76,t≥7; 1. wr

sergij07 [2.7K]

$f(t)=\begin{cases}0&\text{for }t$

Recall that

$u(t)=\begin{cases}0&\text{for }t$

Take it one piece at a time. For $t\ge0$ , we can scale $u(t)$ by -5:

$-5u(t)=\begin{cases}0&\text{for }t$

If we shift the argument by 1 and scale by -5, we have

$-5u(t-1)=\begin{cases}0&\text{for }t$

so if we subtract this from $-5u(t)$ , we'll end up with

$-5u(t)+5u(t-1)=\begin{cases}0&\text{for }t$

For the next piece, we can add another scaled and shifted step like

$-6u(t-1)+6u(t-7)=\begin{cases}0&\text{for }t$

so that

$-5u(t)+5u(t-1)-6u(t-1)+6u(t-7)=\begin{cases}0&\text{for }t$

For the last piece, we add one more term:

$6u(t-7)=\begin{cases}0&\text{for }t$

and so putting everything together, we get $f(t)$ :

$f(t)\equiv-5u(t)+5u(t-1)-6u(t-1)+6u(t-7)+6u(t-7)$
$f(t)\equiv-5u(t)-u(t-1)+12u(t-7)$

5 0

3 years ago

Need help to solve. ​

Need help to solve.