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Shtirlitz [24]
3 years ago
10

What is the slope of a trend line that passes through the points (5, 80) and (7, 65)?

Mathematics
2 answers:
klemol [59]3 years ago
7 0

Answer: a

Step-by-step explanation:

took test

Sedaia [141]3 years ago
3 0

The slope of a trend line that passes through the points (5, 80) and (7, 65) is -7.5.

Step-by-step explanation:

If the line is passing through two points (x1, y1) and (X2, y2). The slope (m) can be calculated using following formula.

m = \frac{y2-y1}{x2-x1}

In this case,

x1  = 5

x2 = 7

y1  = 80

y2 =  65

By putting the values in formula, we get

m = \frac{(65-80)}{7-5}

m = \frac{(-15)}{2}

or

m = -7.5

Therefore, the slope of a trend line that passes through the points (5, 80) and (7, 65) is -7.5.

Learn more:

The following links have more information about slope

brainly.com/question/2586096

brainly.com/question/1978312

Keywords: slope

#learnwithBrainly

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Find the reciprocal of the expression. 10b/2b + 8
Alexus [3.1K]
Comment
I think you need brackets to clarify what you mean. I think it should be written as 
10b/(2b + 8) 

If that is the case the reciprocal is

(2b + 8)/10b You just turn everything up side down. There are technical ways of doing this, but the easiest way is just to do what I just did. 

Put the numerator in  the denominator,
Put the denominator in the numerator.

You could simplify this a bit.
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which reduces further.

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Just to make sure you understand where that b is, I will do this in

Latex.\frac{2b + 8}{10b} =  \frac{2b}{10b} +  \frac{8}{10b} =  \frac{2}{10} + \frac{4}{5b} =  \frac{1}{5} +  \frac{4}{5b}

Alternate answer
If you do mean what your wrote then the reciprocal is 2b / 10b + 8 which is 1/5 + 8 = 8 + 0.2 = 8.2 

The 8 has nothing to do with the reciprocal under these conditions.

The answer
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