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kotegsom [21]
3 years ago
9

Line 9 and 10

Mathematics
2 answers:
bogdanovich [222]3 years ago
7 0

Answer:

Step-by-step explanation:

insens350 [35]3 years ago
6 0

Answer:

I think the answer could be 188,393

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Which of the following shows the true solution to the logarithmic equation 3 log Subscript 2 Baseline (2 x) = 3 x = negative 1 x
s2008m [1.1K]

Answer:

x = 1

Step-by-step explanation:

Using the rules of logarithms

log x^{n} ⇔ n log x

log_{b} x = n ⇔ x = b^{n}

Given

3log_{2} (2x) = 3

log_{2} (2x)³ = 3

(2x)³ = 2³

8x³ = 8 ( divide both sides by 8 )

x³ = 1 ( take the cube root of both sides )

x = 1

7 0
3 years ago
Please very soon I offer the crown !!! + 10 points urgently !!!
krek1111 [17]

Answer:

For 90:

9 10p coins

7 10p coins and 1 20p coin

5 10p coins and 2 20 p coins

3 10p coins and 3 20p coins

For 60:

6 10p coins

4 10p coins and 1 20p coin

2 10p coins and 2 20p coins

3 20p coins

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
g A population is infected with a certain infectious disease. It is known that 95% of the population has not contracted the dise
trasher [3.6K]

Answer:

There is approximately 17% chance of a person not having a disease if he or she has tested positive.

Step-by-step explanation:

Denote the events as follows:

<em>D</em> = a person has contracted the disease.

+ = a person tests positive

- = a person tests negative

The information provided is:

P(D^{c})=0.95\\P(+|D) = 0.98\\P(+|D^{c})=0.01

Compute the missing probabilities as follows:

P(D) = 1- P(D^{c})=1-0.95=0.05\\\\P(-|D)=1-P(+|D)=1-0.98=0.02\\\\P(-|D^{c})=1-P(+|D^{c})=1-0.01=0.99

The Bayes' theorem states that the conditional probability of an event, say <em>A</em> provided that another event <em>B</em> has already occurred is:

P(A|B)=\frac{P(B|A)P(A)}{P(B|A)P(A)+P(B|A^{c})P(A^{c})}

Compute the probability that a random selected person does not have the infection if he or she has tested positive as follows:

P(D^{c}|+)=\frac{P(+|D^{c})P(D^{c})}{P(+|D^{c})P(D^{c})+P(+|D)P(D)}

              =\frac{(0.01\times 0.95)}{(0.01\times 0.95)+(0.98\times 0.05)}\\\\=\frac{0.0095}{0.0095+0.0475}\\\\=0.1666667\\\\\approx 0.1667

So, there is approximately 17% chance of a person not having a disease if he or she has tested positive.

As the false negative rate of the test is 1%, this probability is not unusual considering the huge number of test done.

7 0
3 years ago
Please help me and explain pleas.
hichkok12 [17]
C) 2 5/16 that is the answer. Hope this helps
6 0
3 years ago
Read 2 more answers
Solve using inequalities <br>6&lt;k/9+7​
valentinak56 [21]

Answer:

Let's solve your problem step-by-step:

6 < k/9 +7

Step 1: Simplify both sides of the inequality:

6<1/9 k+7

Step 2: Flip the equation:

1/9 k+7 > 6

Step 3: Subtract 7 from both sides:

1/9 k+7 -7 > 6-7

1/9 k > - 1

Step 4: Multiply both sides by 9:

9 * (1/9) > (9) * (-1)

Answer: <u>k > − 9</u>

Step-by-step explanation:

Please mark me Brainliest!

Hope this helps! Good luck! :)

3 0
3 years ago
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