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juin [17]
3 years ago
6

Please help me this is due tonight

Mathematics
1 answer:
hram777 [196]3 years ago
8 0
ANSWER:

Substitution prop of equality.

I'm not sure but I think this should be the answer.

Hope this helps! :)
You might be interested in
What is the area of this figure? Round to the tenth if necessary.
Julli [10]

Answer:

<h3>b) 850.1 centimeters.</h3>

Step-by-step explanation:

To find the area of this figure, we must first find the areas of the shapes that compose this figure.

This figure is made up of a rectangle and a semicircle.

Remember: To find the area of a semicircle, multiply the radius by itself twice, then multiply the product pi, lastly divide the product by 2.

a=\pi r^2/2

<u>3.14 will be used for pi!</u>

To find the area of a rectangle, multiply the length by the width. The product is the area of the rectangle.

a=lw

Now, let's solve.

The diameter of the semicircle is 32 centimeters.

To find the radius of a semicircle, divide the diameter by 2.

32/2=16

The radius of the semicircle is 16 centimeters.

Now that we have the radius, we can find the area of the semicircle.

\pi 16^2/2=401.92

The area of the semicircle is 401.92 centimeters.

Furthermore, we find the area of the rectangle.

14*32=448.

The area of the circle is 448 centimeters.

Next, we add the areas of both shapes to find the area of this figure.

401.92+448

=849.92

The final step is to round 849.92 to the nearest tenth.

Even though 849.92 to rounded to the nearest tenth is 849.9, there is no answer choice for this. The closest one to this answer is choice 'b.'

I, therefore, believe the area of this figure is 850.1 centimeters.

3 0
3 years ago
What are the vertical and horizontal asymptotes for the function f(x)=<br> 3x2/x2-4
Alecsey [184]

Answer:  f(x) will have vertical asymptotes at x=-2 and x=2 and horizontal asymptote at y=3.

Step-by-step explanation:

Given function: f(x)=\dfrac{3x^2}{x^2-4}

The vertical asymptote occurs for those values of x which make function indeterminate or denominator 0.

i.e. x^2-4=0\Rightarrow\ x^2=4\Rightarrow\ x=\pm2

Hence, f(x) will have vertical asymptotes at x=-2 and x=2.

To find the horizontal asymptote , we can see that the degree of numerator and denominator is same i.e. 2.

So, the graph will horizontal asymptote at y=\dfrac{\text{Coefficient of }x^2\text{ in numerator}}{\text{Coefficient of }x^2\text{ in denominator}}

i.e. y=\dfrac{3}{1}=3

Hence, f(x) will have horizontal asymptote at y=3.

3 0
3 years ago
Use the list method to write "The odd integers between 2 and 15". {2, 3, 5, 7, 9, 11, 13, 15} {3, 5, 7, 9, 11, 13} {3, 5, 7, 9,
Sladkaya [172]

The answer would be {3, 5, 7, 9, 11, 13, 15}.

6 0
3 years ago
10z^2 -2z-2<br> 10z <br> 2<br> −2z−2
KatRina [158]

Two solutions were found :

z =(2-√-116)/-20=1/-10+i/10√ 29 = -0.1000-0.5385i

z =(2+√-116)/-20=1/-10-i/10√ 29 = -0.1000+0.5385i

Step-by-step explanation:

5 0
2 years ago
. For the function rule y = -2x - 3, provide the x-y coordinates of the y-intercept and the x-intercept. Show your work.
VashaNatasha [74]
The answer would be  3,2
5 0
3 years ago
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