Math help please will mark brainliest

Nine friends share 8 bags of trail mix equally.what fraction of a bag of trail mix does each friend get?

kodGreya [7K]

Answer:

By doing 3 divided by 5, you will get 3/5 of trail mix per person.

Step-by-step explanation:

4 0

3 years ago

Simplify and reduce to the lowest terms. <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B-7%7D%7B12%7D%20" id="TexFormula1" t

Paladinen [302]

When you divide two fractions, you're actually multiplying one of them by the reciprocal of the other. First, find the reciprocal of the second fraction by flipping it upside down. Then, multiply it by the first fraction. (Numerator x numerator and denominator x denominator)

$\frac{-7}{12}$ ÷ $\frac{2}{3}$ Replace the second fraction with it's reciprocal
$\frac{-7}{12}$ x $\frac{3}{2}$ Multiply (-7 x 3 and 12 x 2)
$\frac{-21}{24}$ Both 21 and 24 are divisible by three, so divide them by 3
$\frac{-7}{8}$

6 0

2 years ago

Please help me I will give brainliest

romanna [79]

Answer:

1/9 is c -2/12 is a -0.1 is b

Step-by-step explanation:

PLEASE PUT IN THE ANSWER THEN GIVE BRAINLEIST

4 0

2 years ago

Answers fast please. 1.) y=x−63x+2y=8 Use the substitution method. A.) (4, −2) B.) (14, 8) C.) (0, −6) D.) (3, −3) 2.) What is t

GrogVix [38]

QUESTION 1

The given system of equation is

$y=x-6...eqn1$

and

$3x+2y=8...eqn2$

Let us substitute equation (1) into equation (2) to get,

$3x+2(x-6)=8$

We expand the bracket to get,

$3x+2x-12=8$

We simplify to get.

$5x-12=8$

We group like terms to get

$5x=8+12$

$\Rightarrow 5x=20$

$\Rightarrow x=4$

We now substitute $x=4$ in to equation (1) to obtain,

$y=4-6=-2$

The correct answer is option A.

QUESTION 2

The given system of equations is

$y-x=9...eqn1$

and

$10+2x=-2y...eqn2$

We make y the subject in equation (2) to get,

$y=-x-5..eqn3$

We put equation (3) into equation (1) to obtain,

$-x-5-x=9$

We group like terms to get,

$-x-x=9+5$

This implies that,

$-2x=14$

We divide through by $-2$ to get,

$x=-7$

Hence the x-coordinate is $-7$

QUESTION 3

The given system is

$y=3x-1..eqn1$

and

$x-y=-9...eqn2$

We make $x$ the subject in equation (2) to get,

$x=y-9...eqn3$

We put equation (3) into equation (1) to obtain,

$y=3(y-9)-1$

We expand the bracket to get,

$y=3y-27-1$

Group like terms to get,

$y-3y=-27-1$

We simplify to get;

$-2y=-28$

This implies that,

$y=14$

Therefore the y-coordinate is 14.

4 0

3 years ago

Read 2 more answers

A line is tangent to the circle x^2+y^2=41, at the point (-4,-5)

VashaNatasha [74]

If the equation of the circle is x^2+ y^2 = 41, we must first understand the parts of the equation.
A general circle's equation is (x-h)^2+(y-k)^2= r^2
(h.k) is the radius of the circle
r is the radius of the circle
Another useful fact to know is that tangent lines touch the circle at one point (4,5)

Since in our original equation there are no h or k values, we can assume that the center of the circle is (0,0).

The formula for slope is Y1-Y2
X1-X2
We can break this down with our two points (center and tangent)
(0,0) and (-4,-5)
(X1,Y1) and (X2,Y2)

therefore, we will put the equation as such
0-(-5)= 5 = 5
0-(-4)= 4  4

this is our slope from the center to the point of tangency.

We know that tangent lines are perpendicular to the radius, which we've already found the slope of. Perpendicular lines are opposite reciprocals of the line they are perpendicular to.

Therefore, we take our slope from center to the tangent, and make it opposite and then take the reciprocal of that slope, which will give us the slope of the tangent line itself. (note: reciprocal means flip the numerator and denominator)
5 = -5 = -4
4 4 5

Now, we have a point on the line, and the line's slope. We can use slope-intercept equation to find the equation of the line.

Slope-int y=mx+b
(x,y) is a point,
m is the slope
b is the y intercept ( the point where x=0, or where its on the y axis)

now we plug things in
(-4,-5) is our point,
-4 is our slope
5

-5=-4(-4)+b After we plug things in, solve for b
5

-5= 3.2+b

-1.8= b or b= 1 4
5

Now we just need to rewrite our equation with all our components.
(-4.-5) = point
-4 = slope
5
1 4 = y-intercept
 5

y=-4 x+ 1 4 This is the equation of the tangent line
 5 5

Hope that helped

7 0

3 years ago