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IceJOKER [234]
3 years ago
15

What is the axis of symmetry for f(x)=- 3x^ 2 +18x-7? X=-3 X=3 X=-6 X=6

Mathematics
2 answers:
ValentinkaMS [17]3 years ago
7 0
This is a quadratic equation with a squared "x" variable, and therefore a vertical parabolic graph, and thus, the axis of symmetry will be from the vertex's x-coordinate, hmmmm what is its vertex coordiinate anyway?

\bf \textit{vertex of a vertical parabola, using coefficients}
\\\\
f(x)=\stackrel{\stackrel{a}{\downarrow }}{-3}x^2\stackrel{\stackrel{b}{\downarrow }}{+18}x\stackrel{\stackrel{c}{\downarrow }}{-7}
\qquad \qquad 
\left(-\cfrac{ b}{2 a}~~~~ ,~~~~  c-\cfrac{ b^2}{4 a}\right)
\\\\\\
\left( -\cfrac{18}{2(-3)}~~,~~\qquad  \right)\implies \left( +\cfrac{18}{6}~~,~~\qquad  \right)\implies (3~,\quad )
\\\\\\
\stackrel{\textit{axis of symmetry}}{x=3}
Step2247 [10]3 years ago
6 0

The axis of symmetry is a vertical line through the vertex. 

The vertex is at

x=-b/2a=-18/(2(-3))=3

Second choice.

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