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3 years ago

I need help with this question its due today and I don't understand it.

Mathematics

2 answers:

barxatty [35]3 years ago

8 0

Four puzzles i think

Angelina_Jolie [31]3 years ago

7 0

Answer:

Step-by-step explanation:

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Alyssa spent half of her allowance going to the movies. She washed the family car and earned 7 dollars. What is her weekly allow

Katarina [22]

She gets 18 dollars a week

7 0

3 years ago

What is the slope of the line that contains the points (5, –9) and (5, 9)?

Yakvenalex [24]

It would be: (y2-y1) / (x2-x1) = (9-(-9)/5-5 = 18/0 = undefined

OPTION D IS YOUR ANSWER.........

6 0

3 years ago

Read 2 more answers

Lines k and n intersect on the y-axis

avanturin [10]

a) The equation of line k is:

$y = -\frac{202}{167}x + \frac{598}{167}$

b) The equation of line j is:

$y = \frac{167}{202}x + \frac{1546}{202}$

The equation of a line, in slope-intercept formula, is given by:

$y = mx + b$

In which:

m is the slope, which is the rate of change.
b is the y-intercept, which is the value of y when x = 0.

Item a:

Line k intersects line m with an angle of 109º, thus:

$\tan{109^{\circ}} = \frac{m_2 - m_1}{1 + m_1m_2}$

In which $m_1$ and $m_2$ are the slopes of k and m.

Line k goes through points (-3,-1) and (5,2), thus, it's slope is:

$m_1 = \frac{2 - (-1)}{5 - (-3)} = \frac{3}{8}$

The tangent of 109 degrees is $\tan{109^{\circ}} = -\frac{29}{10}$
Thus, the slope of line m is found solving the following equation:

$\tan{109^{\circ}} = \frac{m_2 - m_1}{1 + m_1m_2}$

$-\frac{29}{10} = \frac{m_2 - \frac{3}{8}}{1 + \frac{3}{8}m_2}$

$m_2 - \frac{3}{8} = -\frac{29}{10} - \frac{87}{80}m_2$

$m_2 + \frac{87}{80}m_2 = -\frac{29}{10} + \frac{3}{8}$

$\frac{167m_2}{80} = \frac{-202}{80}$

$m_2 = -\frac{202}{167}$

Thus:

$y = -\frac{202}{167}x + b$

It goes through point (-2,6), that is, when $x = -2, y = 6$ , and this is used to find b.

$y = -\frac{202}{167}x + b$

$6 = -\frac{202}{167}(-2) + b$

$b = 6 - \frac{404}{167}$

$b = \frac{6(167)-404}{167}$

$b = \frac{598}{167}$

Thus. the equation of line k, in slope-intercept formula, is:

$y = -\frac{202}{167}x + \frac{598}{167}$

Item b:

Lines j and k intersect at an angle of 90º, thus they are perpendicular, which means that the multiplication of their slopes is -1.

Thus, the slope of line j is:

$-\frac{202}{167}m = -1$

$m = \frac{167}{202}$

Then

$y = \frac{167}{202}x + b$

Also goes through point (-2,6), thus:

$6 = \frac{167}{202}(-2) + b$

$b = \frac{(2)167 + 202(6)}{202}$

$b = \frac{1546}{202}$

The equation of line j is:

$y = \frac{167}{202}x + \frac{1546}{202}$

A similar problem is given at brainly.com/question/16302622

7 0

2 years ago

Add the two expressions. 2x + 6 and 6x −1 Enter your answer in the box.

MA_775_DIABLO [31]

Answer:

8x +5

Step-by-step explanation:

The sum is found by combining "like" terms—those that have the same arrangement of variables.

The first expression, 2x +6, has terms 2x and 6.

The second expression, 6x -1, has terms 6x and -1.

In each case, the first term listed is first-degree in the variable x. These are "like" terms, so can be added:

... 2x +6x = (2+6)x = 8x

The second term listed in each case is a constant. These are "like" terms, so can be added:

... 6 + (-1) = 5

Then the sum of the given expressions is the sum of the results from adding like terms:

... 8x + 5

4 0

3 years ago

34=−2t can u help me

lys-0071 [83]

34 = -2t....divide both sides by -2
(-34/2) = (-2/-2)t
- 17 = 1t, or just t

so ur answer is : t = -17

3 0

3 years ago