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Romashka [77]
3 years ago
12

I need help with this question its due today and I don't understand it.

Mathematics
2 answers:
barxatty [35]3 years ago
8 0
Four puzzles i think
Angelina_Jolie [31]3 years ago
7 0

Answer:

4

Step-by-step explanation:

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Alyssa spent half of her allowance going to the movies. She washed the family car and earned 7 dollars. What is her weekly allow
Katarina [22]

She gets 18 dollars a week

7 0
3 years ago
What is the slope of the line that contains the points (5, –9) and (5, 9)?
Yakvenalex [24]

It would be: (y2-y1) / (x2-x1) = (9-(-9)/5-5 = 18/0 = undefined

OPTION D IS YOUR ANSWER.........

6 0
3 years ago
Read 2 more answers
Lines k and n intersect on the y-axis
avanturin [10]

a) The equation of line k is:

y = -\frac{202}{167}x + \frac{598}{167}

b) The equation of line j is:

y = \frac{167}{202}x + \frac{1546}{202}

The equation of a line, in <u>slope-intercept formula</u>, is given by:

y = mx + b

In which:

  • m is the slope, which is the rate of change.
  • b is the y-intercept, which is the value of y when x = 0.

Item a:

  • Line k intersects line m with an angle of 109º, thus:

\tan{109^{\circ}} = \frac{m_2 - m_1}{1 + m_1m_2}

In which m_1 and m_2 are the slopes of <u>k and m.</u>

  • Line k goes through points (-3,-1) and (5,2), thus, it's slope is:

m_1 = \frac{2 - (-1)}{5 - (-3)} = \frac{3}{8}

  • The tangent of 109 degrees is \tan{109^{\circ}} = -\frac{29}{10}
  • Thus, the slope of line m is found solving the following equation:

\tan{109^{\circ}} = \frac{m_2 - m_1}{1 + m_1m_2}

-\frac{29}{10} = \frac{m_2 - \frac{3}{8}}{1 + \frac{3}{8}m_2}

m_2 - \frac{3}{8} = -\frac{29}{10} - \frac{87}{80}m_2

m_2 + \frac{87}{80}m_2 = -\frac{29}{10} + \frac{3}{8}

\frac{167m_2}{80} = \frac{-202}{80}

m_2 = -\frac{202}{167}

Thus:

y = -\frac{202}{167}x + b

It goes through point (-2,6), that is, when x = -2, y = 6, and this is used to find b.

y = -\frac{202}{167}x + b

6 = -\frac{202}{167}(-2) + b

b = 6 - \frac{404}{167}

b = \frac{6(167)-404}{167}

b = \frac{598}{167}

Thus. the equation of line k, in slope-intercept formula, is:

y = -\frac{202}{167}x + \frac{598}{167}

Item b:

  • Lines j and k intersect at an angle of 90º, thus they are perpendicular, which means that the multiplication of their slopes is -1.

Thus, the slope of line j is:

-\frac{202}{167}m = -1

m = \frac{167}{202}

Then

y = \frac{167}{202}x + b

Also goes through point (-2,6), thus:

6 = \frac{167}{202}(-2) + b

b = \frac{(2)167 + 202(6)}{202}

b = \frac{1546}{202}

The equation of line j is:

y = \frac{167}{202}x + \frac{1546}{202}

A similar problem is given at brainly.com/question/16302622

7 0
2 years ago
Add the two expressions.<br><br> 2x + 6 and 6x −1<br><br> Enter your answer in the box.
MA_775_DIABLO [31]

Answer:

8x +5

Step-by-step explanation:

The sum is found by combining "like" terms—those that have the same arrangement of variables.

The first expression, 2x +6, has terms 2x and 6.

The second expression, 6x -1, has terms 6x and -1.

In each case, the first term listed is first-degree in the variable x. These are "like" terms, so can be added:

... 2x +6x = (2+6)x = 8x

The second term listed in each case is a constant. These are "like" terms, so can be added:

... 6 + (-1) = 5

Then the sum of the given expressions is the sum of the results from adding like terms:

... 8x + 5

4 0
3 years ago
34=−2t can u help me
lys-0071 [83]
34 = -2t....divide both sides by -2
(-34/2) = (-2/-2)t
- 17 = 1t, or just t

so ur answer is : t = -17
3 0
3 years ago
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