Let Ch and C denote the events of a student receiving an A in <u>ch</u>emistry or <u>c</u>alculus, respectively. We're given that
P(Ch) = 88/520
P(C) = 76/520
P(Ch and C) = 31/520
and we want to find P(Ch or C).
Using the inclusion/exclusion principle, we have
P(Ch or C) = P(Ch) + P(C) - P(Ch and C)
P(Ch or C) = 88/520 + 76/520 - 31/520
P(Ch or C) = 133/520
Using translation concepts, compared to the graph of the base function g(x) = x², the function f(x) was:
- Vertically stretched by a factor of 4.
<h3>What is a translation?</h3>
A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction in it's definition.
In this problem, the base function g(x) = x² was:
- Multiplied by 4, that is, vertically stretched by a factor of 4.
- Shifted left 9 units, as x -> x + 9.
More can be learned about translation concepts at brainly.com/question/4521517
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Using the least common factor, it is found that:
- a) 60 packages should be bought.
- b) There will be 5 filled goody bags.
<h3>
Least Common Factor:</h3>
- The sizes of the packages are: 10, 6, 15 and 12.
- To fill each bag and have no left-overs, the number of packages is the <u>least common factor</u> of these amounts.
- The least common factor is found factoring the numbers into prime factors.
Item a:
10 - 6 - 15 - 12|2
5 - 3 - 15 - 6|2
5 - 3 - 15 - 3|3
5 - 1 - 5 - 1|5
1 - 1 - 1 - 1
Hence, lcf(10,6,15,2) = 2 x 2 x 3 x 5 = 60.
60 packages should be bought.
Item b:
Goody bags are in packages of 12, hence:
60/12 = 5.
There will be 5 filled goody bags.
To learn more about the least common factor, you can take a look at brainly.com/question/24873870
Answer:
1/10 or 10%
Step-by-step explanation:
1/4 x 2/5 = 1/10 (10%)
x=8.9 because when you square it and divide you get 39.6.. rounded to 40.
