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Vaselesa [24]
3 years ago
5

What is nearest whole number of 14.603

Mathematics
2 answers:
zhenek [66]3 years ago
7 0
The nearest whole number to 14.603 would be 15. 

Why?

Well that's because we will look at the tenths place fore this question which would be 14.603 (6). This number is AFTER 5, so we will round to the next number. But if 6 was LESS than 5 it would stay 14, but since its 6 we will take it up to 15.

So, 14.603 rounded to the nearest whole number is 15.

Hope i helped ya!!!!!!!!!! 
motikmotik3 years ago
5 0
15 is the nearest whole number to that number
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Find the slope of the line passing through the<br> points<br> (-9, 2) and (7, 2).
Alisiya [41]

Answer:

0

Step-by-step explanation:

-y₁ + y₂\-x₁ + x₂ = m

\frac{ - 2 + 2}{9 + 7}  =  \frac{0}{16}  = 0

I am joyous to assist you anytime.

3 0
3 years ago
Arrange the steps from start to finish to factor this expression using the grouping method x^2-5x-24 drag the tiles to the corre
rosijanka [135]

Answer:

(x - 8)(x + 3)

Step-by-step explanation:

x² - 5x - 24

Consider the factors of - 24 which sum to give the coefficient of the x- term (- 5)

The factors are - 8 and + 3 , since

- 8 × + 3 = - 24 and - 8 + 3 = - 5

Use these factors to split the x- term

x² - 8x + 3x - 24 ( factor the first/second and third/fourth terms )

= x(x - 8) + 3(x - 8) ← factor out (x - 8) from each term

= (x - 8)(x + 3) ← in factored form

7 0
2 years ago
Word problem:
Jlenok [28]

Answer:

Below.

Step-by-step explanation:

30 kg 500g + 28kg 700g

= 58kg + 1200g

= 59kg 200g.

Difference

= 30 kg 500g - 28kg 700g

= 2kg + 500 - 700

= 2kg - 200g

= 1kg 800g.

3 0
3 years ago
A rectangle is four times as long as it is wide. If its length were diminished by 6 meters and its width were increased by 6 met
valkas [14]

Answer:

Length equals 16 and Width equals 4

Step-by-step explanation:

First let us create an equation. We can use L and W for length and width.

If the length is 4 times the width, then we end up with: L = 4W

It then says, " If its length were diminished by 6 meters and its width were increased by 6 meters, it would be a square."

Since a square has an equal length and width then we end up with:

L - 6 = W + 6

Knowing this we can just substitute the first equation into the second one leaving us with: 4W - 6 = W + 6

We then remove a W from both sides so that the right side is left with a 6, and add 6 to both sides to remove the -6 from the left one.

This leaves us with 3W = 12

W = 4, and if we put that into our first equation, L = 4W, then Length equals 16, and Width equals 4. We can check this by putting it into the 2nd equation. 16 - 6 = 4 + 6.

7 0
1 year ago
What is the answer to this question?
sukhopar [10]
First plug in f and g:
3 x^{2} +1-  [1-x]
Then distribute 3 x^{2} +1-1+x
Combine like terms
3 x^{2} +x
Now plug in 2 for x
3( 2^{2} )+2
3(4)+2=12+2=14

Hope that helps
8 0
3 years ago
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