Doing this so I can ask sorry
The completely factored expression of 2x^2 + 4x + 3xy + 6y is (2x + 3y)(x + 2)
<h3>How to factor the polynomial?</h3>
The expression is given as:
2x^2 + 4x + 3xy + 6y
Group the expression into two
[2x^2 + 4x] + [3xy + 6y]
Factor out each group
2x(x + 2) + 3y(x + 2)
Factor out x + 2
(2x + 3y)(x + 2)
Hence, the completely factored expression of 2x^2 + 4x + 3xy + 6y is (2x + 3y)(x + 2)
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Answer:
A.
Step-by-step explanation:
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Answer:
6231
Step-by-step explanation:
We want to find the value of cot(θ) given that sin(θ) = 3/8 and θ is an angle in a right triangle, we will get:
cot(θ) = (√55)/3
So we know that θ is an acute angle in a right triangle, and we get:
sin(θ) = 3/8
Remember that:
- sin(θ) = (opposite cathetus)/(hypotenuse)
- hypotenuse = √( (opposite cathetus)^2 + (adjacent cathetus)^2)
Then we have:
opposite cathetus = 3
hypotenuse = 8 = √(3^2 + (adjacent cathetus)^2)
Now we can solve this for the adjacent cathetus, so we get:
adjacent cathetus = √(8^2 - 3^2) = √55
And we know that:
cot(θ) = (adjacent cathetus)/(opposite cathetus)
Then we get:
cot(θ) = (√55)/3
If you want to learn more, you can read:
brainly.com/question/15345177
