All categories

4 years ago

Write a statistical question to find out students favorite flavor of gum

Mathematics

2 answers:

Reil [10]4 years ago

7 0

Answer:

Step-by-step explanation:

Firstly, we need to understand what statistical question is!

A statistical question is the question you may have in your survey and you expect to have more than one possible answer. Because you are interested in the distribution and tendency of those answers.

For example, "Do you like strawberry gum?" This is not a statistical question because you only yes or no.

In your case, you can create a statistical one like:

What are your favorite flavor of gum?

Students will have a wide range of answers like: banana flavor, strawberry flavor or mint flavor.... after that you will do a statistic to find out how many percentage of students like banana flavor, how many percentage of students like mint flavor......

Hope it will find you well.

igomit [66]4 years ago

6 0

25% of the class likes mint gum, 5% likes orange, 20% likes raspberry lemonade, of the remaining % likes cherry. how much is the remaining % of students?

You might be interested in

Billy was counting the number of wheels and bike seats at the playground. He saw tricycles and bicycles. He counted 79 wheels an

mart [117]

I think the answer is 25.5. Although, I don't know how you would have half a bike unless there was a 3 wheel bike which would make the answer 24.

7 0

4 years ago

On Saturday, you bowl at Mar vista Bowl, where renting shoes costs $2 and each game bowled is $3.50. On Sunday, you bowl at Pinz

7nadin3 [17]

Answer:

12 games

Step-by-step explanation:

Let the number of games is g

Total cost at Mar Vista:

3.5g + 2

Total cost at Pinz:

3.25g + 5

Since same amount spent in both places, we have:

3.5g + 2 = 3.25g + 5
3.5g - 3.25 = 5 - 2
0.25g = 3
g = 3/0.25
g = 12

8 0

3 years ago

What is Permutations and Combinations?

marissa [1.9K]

Answer:

See below

Step-by-step explanation:

Permutation is to select an object then arrange it and it cares about the orders while Combination is about only selecting an object without caring the orders.

Permutation can be expressed in math as:

$\displaystyle{_n P _r = \dfrac{n!}{(n-r)!} \ \ \ (n \geq r) }$

where n is a number of total object and r is a number of selected object to arrange. Hence. n cannot be less than r.

Now let's see an example of permutation, suppose we have letter A, B and C. I'd like to know how many ways these words can be arranged:

Since there are 3 letters total and 3 selected letters to arrange then:

$\displaystyle{_3 P _3 = \dfrac{3!}{(3-3)!}}\\\\\displaystyle{_3 P _3 = \dfrac{3 \times 2 \times 1}{0!}}\\\\\displaystyle{_3 P _3 = \dfrac{6}{1}}\\\\\displaystyle{_3 P _3 = 6}$

Therefore, there are 6 ways to arrange the letters - we can also demonstrate visually:

ABC - 1

ACB - 2

BAC - 3

BCA - 4

CAB - 5

CBA - 6

Notice that if you do visually, you'll get the same answer as the calculation of permutation!

----

Combination can be expressed mathematically as:

$\displaystyle{_n C _r = \dfrac{n!}{(n-r)!r!} = \dfrac{_n P _r}{r!} \ \ \ (n \geq r) }$

The difference between permutation and combination is that you only find how many ways you can select object in combination. Therefore, no arrange and doesn't care about order, just ways to select.

Suppose we have same 3 letters: A, B and C. I want to find how many ways I can select these 3 letters:

Since there are 3 letters total and 3 selected letters:

$\displaystyle{_3 C _3 = \dfrac{3!}{(3-3)!3!}}\\\\\displaystyle{_3 C _3 = \dfrac{3!}{0!3!}}\\\\\displaystyle{_3 C _3 = \dfrac{3!}{3!}}\\\\\displaystyle{_3 C _3 = 1}$