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FinnZ [79.3K]
3 years ago
7

JJ PLEASE HELP ME THX WILL MARK BRAINLIEST

Mathematics
1 answer:
vlabodo [156]3 years ago
6 0
I’m 100% sure you can check “the answer will be larger than 550”
I don’t really know about the others sorry!
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What is the area of this triangle x1,y1)(x3,y3)1,y1)
Novosadov [1.4K]
Please give it's proper dimensions..

Thanks!
7 0
3 years ago
When a button is pressed, a computer program outputs a random even number greater than 0 less than 8. You press the button 4 tim
EastWind [94]

Answer:

Well all even numbers between 0 and 8 are,

2, 4, 6, 8

Meaning if the button is pressed 4 times 2, 4, 6, or 8 will be outputted.

6 0
3 years ago
Find the measure of the segment indicated.
julsineya [31]
Answer is QM = 18

You can find the length of QM by using Pythagorean theorem. See the attachment.

It is a quadrilateral with 4 equal congruent sides.

If SP = 30, so do the other 3 sides indicated by the tick marks on all 4 sides.

We will call side RQ = the hypotenuse
or side “c” = 30
We know RM is leg “b” = 24
Side “a” is our unknown QM

Our formula is
a^2 + b^2 = c^2

a^2 + 24^2 = 30^2

a^2 + 576 = 900

a^2 = 900 - 576

a^2 = 324

Take square root of both sides to solve a

a = 18

QM = 18

3 0
1 year ago
X and y are normal random variables with e(x) = 2, v(x) = 5, e(y) = 6, v(y) = 8 and cov(x,y)=2. determine the following: e(3x 2y
andriy [413]

The result for the given normal random variables are as follows;

a. E(3X + 2Y) = 18

b. V(3X + 2Y) = 77

c. P(3X + 2Y < 18) = 0.5

d. P(3X + 2Y < 28) = 0.8729

<h3>What is normal random variables?</h3>

Any normally distributed random variable having mean = 0 and standard deviation = 1 is referred to as a standard normal random variable. The letter Z will always be used to represent it.

Now, according to the question;

The given normal random variables are;

E(X) = 2, V(X) = 5, E(Y) = 6, and V(Y) = 8.

Part a.

Consider E(3X + 2Y)

\begin{aligned}E(3 X+2 Y) &=3 E(X)+2 E(Y) \\&=(3) (2)+(2)(6 )\\&=18\end{aligned}

Part b.

Consider V(3X + 2Y)

\begin{aligned}V(3 X+2 Y) &=3^{2} V(X)+2^{2} V(Y) \\&=(9)(5)+(4)(8) \\&=77\end{aligned}

Part c.

Consider P(3X + 2Y < 18)

A normal random variable is also linear combination of two independent normal random variables.

3 X+2 Y \sim N(18,77)

Thus,

P(3 X+2 Y < 18)=0.5

Part d.

Consider P(3X + 2Y < 28)

Z=\frac{(3 X+2 Y-18)}{\sqrt{77}}

\begin{aligned} P(3X + 2Y < 28)&=P\left(\frac{3 X+2 Y-18}{\sqrt{77}} < \frac{28-18}{\sqrt{77}}\right) \\&=P(Z < 1.14) \\&=0.8729\end{aligned}

Therefore, the values for the given normal random variables are found.

To know more about the normal random variables, here

brainly.com/question/23836881

#SPJ4

The correct question is-

X and Y are independent, normal random variables with E(X) = 2, V(X) = 5, E(Y) = 6, and V(Y) = 8. Determine the following:

a. E(3X + 2Y)

b. V(3X + 2Y)

c. P(3X + 2Y < 18)

d. P(3X + 2Y < 28)

8 0
2 years ago
Find the dimensions of a rectangle
gayaneshka [121]
The length of the shorter side is 7 longer side is 12 7+7+12+12 is 38 and 7x12 is 84
4 0
2 years ago
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