All categories

3 years ago

O6. Solve the equation x2=10 a. X= +10 b. X= V10 X= +5 d. X= 5

Mathematics

1 answer:

ANTONII [103]3 years ago

5 0

Answer:

Step-by-step explanation:

You might be interested in

A student ran a distance of 2 1/2 miles each day for 9 days. The student ran a distance of 5 3/4 miles each day for the next 3 d

cestrela7 [59]

Answer:

39.75 miles

Step-by-step explanation:

5 0

2 years ago

One thirdOne third of a number is added to 77, giving a result of at least 33.

alexgriva [62]

Answer:

in my ipinion...

Step-by-step explanation:

let a no.be x

1/3*x+77=33

1/3*x=-44

x=-44*3

x=-132

6 0

2 years ago

Answer???????????????????

andrezito [222]

∠ABC is 180°. ∠ABC-∠ABD=68°. Since line BE ∠DBC, 68 divide by 2 is 34°. So ∠EBC is <span>34°.</span>

7 0

2 years ago

Check Your Understanding Are you more likely to win a random drawing if you crinkle the paper that contains your name before put

IRINA_888 [86]

Answer: hello your question to the given scenerio is missing below is the missing question

question: Does this setting represent a Binomial distribution ?

answer : Yes the setting represents a Binomial distribution

Step-by-step explanation:

The setting represents a Binomial distribution, because the criteria's for a Binomial distribution is all present which are

The random variable ( number of times a crinkled paper is picked ) is represented as Y
Each sample is drawn independently and with replacement
there are only two outcomes ( success or failure )
Number of trials is given as 10
probability of success = 25 / 100 = 0.25

4 0

3 years ago

FURTHER MATHEMATICS Use determinants to solve the systems of equation:

maw [93]

Answer:

Step-by-step explanation:

$\left\{\begin{array}{ccc}2x+1y+2z&=&13\\1x+1y-2z&=&8\\1x+2y+1z&=&11\\\end{array}\right.\\\\\\\Delta=\left| \begin{array}{ccc}2&1&2\\1&1&-2\\1&2&1\end{array}\right| =2*\left| \begin{array}{ccc}1&\frac{1}{2}&1\\1&1&-2\\1&2&1\end{array}\right| =2*\left| \begin{array}{ccc}1&\frac{1}{2}&1\\0&\frac{1}{2}&-3\\0&1&3\end{array}\right| =2*(\frac{3}{2}+3)=9\\\\$

$\Delta_1=\left| \begin{array}{ccc}13&1&2\\8&1&-2\\11&2&1\end{array}\right| =2*\left| \begin{array}{ccc}13&1&2\\8&1&-2\\\frac{11}{2}& 1&\frac{1}{2}\end{array}\right| =2*\left| \begin{array}{ccc}13&1&2\\-5&0&-4\\\frac{-5}{2}& 0&\frac{5}{2}\end{array}\right| \\\\=2*(-1)*(\frac{-25}{2}-\frac{20}{2}) =45\\$

$\Delta_2=\left| \begin{array}{ccc}2&13&2\\1&8&-2\\1&11&1\end{array}\right| \\\\\\=\left| \begin{array}{ccc}3&21&0\\3&30&0\\1&11&1\end{array}\right| \\\\\\=1*(90-63) =27\\$

$\Delta_3=\left| \begin{array}{ccc}2&1&13\\1&1&8\\1&2&11\end{array}\right| \\\\\\=\left| \begin{array}{ccc}0&-1&-3\\0&-1&-3\\1&2&11\end{array}\right| \\\\\\=0\\$

$\left\{\begin{array}{ccc}x=\dfrac{\Delta_1}{\Delta}=\dfrac{45}{9}=5\\\\y=\dfrac{\Delta_2}{\Delta}=\dfrac{27}{9}=3\\\\z=\dfrac{\Delta_3}{\Delta}=\dfrac{0}{9}=0\\\end{array}\right.$

8 0

3 years ago

O6. Solve the equation x2=10 a. X= +10 b. X= V10 X= +5 d. X= 5​

O6. Solve the equation x2=10 a. X= +10 b. X= V10 X= +5 d. X= 5