Answer:
1/2
Step-by-step explanation:
the probability of the die rolling an even number = the probability of the die rolling an odd number =1/2
Let us name these 2 dice as A and B
One die can roll an even and the other can roll an odd, in the following cases
A rolls even and B rolls odd. The probability of this happening =1/2×1/2
A rolls odd and B rolls even. The probability of this happening =1/2×1/2
∴ The required probability
=1/2×1/2+1/2×1/2
=1/4+1/4
=1/2
Answer:
41 degrees
Step-by-step explanation:
just subtract
Problem 7)
The answer is choice B. Only graph 2 contains an Euler circuit.
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To have a Euler circuit, each vertex must have an even number of paths connecting to it. This does not happen with graph 1 since vertex A and vertex D have an odd number of vertices (3 each). The odd vertex count makes it impossible to travel back to the starting point, while making sure to only use each edge one time only.
With graph 2, each vertex has exactly two edges attached to it. So an Euler circuit is possible here.
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Problem 8)
The answer is choice B) 5
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Work Shown:
abc base 2 = (a*2^2 + b*2^1 + c*2^0) base 10
101 base 2 = (1*2^2 + 0*2^1 + 1*2^0) base 10
101 base 2 = (1*4 + 0*2 + 1*1) base 10
101 base 2 = (4 + 0 + 1) base 10
101 base 2 = 5 base 10
Answer:
slope: 2.5
y-intercept: -7
equation: 2.5x - 7
Step-by-step explanation:
I hope I helped. Sorry if I'm wrong :(
If you would like an explanation I'd be glad to give one.
<span>Joey, divide the total of 321 by 3. that's the number of adult tickets. double that answer and that's the number of student tickets.</span>
