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3 years ago

Police investigating traffic accidents often estimate the speed of a vehicle by measuring

Mathematics

1 answer:

klio [65]3 years ago

4 0

Answer:

tttttttttttttttttttttttttttttttttt

Step-by-step explanation:

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What is the simplest form of this expression? -x^3(5x+1)+4x^4

Fantom [35]

Answer:

-x^3*(x + 1)

Step-by-step explanation:

Perform the indicated multiplication and then write out all the terms in descending order by powers of x:

-x^3(5x+1)+4x^4 = -5x^4 - x^3 + 4x^4

= -x^4 - x^3, or = -x^3*(x + 1)

7 0

2 years ago

An insurance company sells automobile liability and collision insurance. Let X denote the percentage of liability policies that

qaws [65]

Answer:

-764.28

Step-by-step explanation:

Given the joint cumulative distribution of X and Y as

$F(x,y) = \frac{xy(x+y)}{2000000}\ \ \ \, \ 0\leq x100, 0\leq y\leq 100$

#First find $F_x$ and probability distribution function , $f_x(x)$ :

$F_x(x)=F(x,100)\\\\\\=\frac{100x(x+100)}{2000000}\\\\\\\\=\frac{100x^2+10000x}{2000000}\\\\\\=>f_x(x)=\frac{x}{10000}+\frac{1}{200}$

#Have determined the probability distribution unction , $f_x(x)$ , we calculate the Expectation of the random variable X:

$E(X)=\int\limits^{100}_0 \frac{x^2}{10000}+\frac{x}{200} dx \\\\\\\\=|\frac{x^3}{30000}+\frac{x^2}{400}|\limits^{100}_0\\\\=58.33\\\\$

#We then calculate $E(X^2)$ :

$E(X^2)=\int\limits^{100}_0 \frac{x^3}{10000}+\frac{x^2}{200}\ dx\\\\=\frac{x^4}{40000}+\frac{x^3}{600}|\limits^{100}_0=4166.67\\\\Var(X)=E(X^2)-(E(X))^2=4166.67-58.33^2\\\\Var(X)=764.28$

Hence, the Var(X) is 764.28

4 0

3 years ago

Sorry the last one i put was the wrong one haha

Lunna [17]

Answer:

Step-by-step explanation:

In 7 years, Jose will be his age + 7 years.

5 0

3 years ago

Read 2 more answers

What is x+7/10=-1/5??

Fudgin [204]

Answer:

x=-9/10

Step-by-step explanation:

7 0

2 years ago

Write an expression for the calculation double the number 18 and then add 14 divided in half

Yuki888 [10]

(18 x 2) +14/2
hope this helps:)

7 0

3 years ago

Read 2 more answers