1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lakkis [162]
3 years ago
15

The table shows the number of hours two groups of teens spent on science and math homework last week. Each group was made up of

10 teens. 13- to 14-year olds 10 9 11 8 10 10 2 7 8 12 15- to 16-year olds 12 10 8 11 12 12 6 4 4 10 Select from the drop-down menus to correctly complete each statement. The mean hours the groups of teens spent studying is , The range for the two groups of of teens is .
Mathematics
2 answers:
Ghella [55]3 years ago
7 0

Answer: The mean hours the groups of teens spent studying is little bit greater for  15- to 16-year old teen or about same .

The range range for the two groups of of teens is greater for 13- to 14-year old teens.

Step-by-step explanation:

We know that the mean of a data is given by :-

\text{Mean}=\dfrac{\text{Sum of all observations}}{\text{Number of observations}}

Range = largest observation - least observation

From the given table :

The mean hours spent by 13- to 14-year olds is given by :-

\text{Mean}=\dfrac{87}{10}=8.7

\text{Range=12-2=10}

The mean hours spent by 15- to 16-year olds is given by :-

\text{Mean}=\dfrac{89}{10}=8.9

\text{Range=12-4=8}

The mean hours the groups of teens spent studying is little bit greater for  15- to 16-year old teen or can say about same.

The range range for the two groups of of teens is greater for 13- to 14-year old teens.

KonstantinChe [14]3 years ago
5 0
The answer's are:
1. About the same.
2. Greater for the 13 - 14 year old's.


Hope this helps!
You might be interested in
Solve 8(3x-4)=4x-2. Help
FinnZ [79.3K]
X = 3/2

<em><u>I hope this could help!</u></em>
8 0
3 years ago
Read 2 more answers
ASAP!!! Help me please this is due in a day! And I got so confused........ So can you guys help? By filling in the blanks(empty
Marina86 [1]

hello mai brou tenkuiusnriejqbe

4 0
2 years ago
What is the surface area of a cube that has a side length of 2.2 meters?
zubka84 [21]

Answer:

the answer is c 29.04 meters squared

Step-by-step explanation:

first you multiply 2.2 by 2.2 to get 4.84 then you multiply that by 6 to account for all of the faces

5 0
2 years ago
Read 2 more answers
Solve this and get 20 points
VikaD [51]

take x =initial deposit amount. then make equation:

x+75.5+55.25-25.15-18.65 = 210.85

simplify:

x+86.95 = 210.85

x=210.85 - 86.95

x=123.90

so Initial deposit amount is $123.90

check:  210.85+18.65+25.15-55.25-75.5 = 123.9

123.9 = 123.9

4 0
3 years ago
HELPPPP PLEASEEEE will give brainliest ​
ycow [4]

Answer:

I think it's the 3rd or fourth one. I'm not positive tho

8 0
2 years ago
Other questions:
  • The table shows the height increases,in inches,of some girls in Gina’s class from last month to this month. Gina 3/8. Maxine 2/3
    15·1 answer
  • What is 56/100 in its simplest form
    12·1 answer
  • the students in Mr. hardings gym class went on a class ski trip. Each student paid $25 and the school paid a total of $300. Alto
    14·2 answers
  • You will get 25 points (06.01) 34 + 3 ⋅ 5 = ____. (Input whole numbers only.) Numerical Answers Expected!
    6·1 answer
  • The measure of angle W is 19 degrees more than three times the measure of angle V if the sum of the measures of the two angles i
    10·1 answer
  • Could somebody help me with this geometry question?
    11·1 answer
  • 4/5 + 2/3 =<br>1 1/2-2/6=​
    6·2 answers
  • if 60% of your class likes to play basketball at recess and there are 30 students in your class, how many like playing basketbal
    11·1 answer
  • Find x value <br><img src="https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B3%7D%20%20%2B%20%20%7Bx%7D%5E%7B2%7D%20%20%2B%208x%20%2B%2012
    12·1 answer
  • Write and equation based on the graph. Please help me 20 points!
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!