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2 years ago

Find the slope of the line that passes through A(0,−5) and B(3,−4)

Mathematics

1 answer:

Genrish500 [490]2 years ago

5 0

Answer:

1/3

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-4-(-5))/(3-0)

m=(-4+5)/3

m=1/3

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3 years ago

Which of the following theorems verifies that ABC~WXY?

Bumek [7]

Answer:

The correct answer is option B. AA

Step-by-step explanation:

Given two triangle:

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The dimensions given in $\triangle ABC$ are:

$\angle A = 27^\circ\\\angle B = 90^\circ$

We know that the sum of three angles in a triangle is equal to $180^\circ$ .

$\angle A+\angle B+\angle C = 180^\circ\\\Rightarrow 27+90+\angle C=180^\circ\\\Rightarrow \angle C = 63^\circ$

The dimensions given in $\triangle WXY$ are:

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We know that the sum of three angles in a triangle is equal to $180^\circ$ .

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2 years ago

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Roman55 [17]

Answer:

Step-by-step explanation:

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3 years ago

PLEASE HELP L has y-intercept (0,5) and is perpendicular to the line with equation y=1/3x+1

marin [14]

Answer:

y=-3x+5

Explanation:

Given a line L such that:

• L has y-intercept (0,5); and

• L is perpendicular to the line with equation y=(1/3)x+1.

We want to find the equation of the line in the slope-intercept form.

The slope-intercept form of the equation of a straight line is given as:

$\begin{equation} y=mx+b\text{ where }\begin{cases}m={slope} \\ b={y-intercept}\end{cases} \end{equation}$

Comparing the given line with the form above:

$y=\frac{1}{3}x+1\implies Slope,m=\frac{1}{3}$

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• Two lines are perpendicular if the product of their slopes is -1.

Let the slope of L = m1.

Since L and y=(1/3)x+1 are perpendicular, therefore:

$\begin{gathered} m_1\times\frac{1}{3}=-1 \\ \implies Slope\text{ of line L}=-3 \end{gathered}$

The y-intercept of L is at (0,5), therefore:

$y-intercept,b=5$

Substitute the slope, m=-3, and y-intercept, b=5 into the slope-intercept form.

$\begin{gathered} y=mx+b \\ y=-3x+5 \end{gathered}$

The equation of line L is:

$y=-3x+5$

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