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Sliva [168]
3 years ago
10

Berkshire Inc. had revenues of $379,000 in its first year of operations. The company has not collected on $45,900 of its sales a

nd still owes $38,500 on $160,000 of merchandise it purchased. There was no inventory on hand at the end of the year. The company paid $33,200 in salaries. The owners invested $46,000 in the business and $21,000 was borrowed on a five-year note. The company paid $1,890 in interest that was the amount owed for the year and paid $8,500 for a two-year insurance policy on the first day of business. Ignore the income tax effect, the net income for the first year for Berkshire is: Multiple Choice $219,000 $262,590 $179,660 $185,800
Business
1 answer:
amid [387]3 years ago
7 0

Answer:

$235,010

Explanation:

The computation of the net income for the year is shown below:

Receipt:  

Cash from customer ($379,000 - $45,900) $333,100

Investment in business  $46,000

Borrowed money on notes $21,000

Total Receipts (A) $400,100

Disbursement:  

Payment to vendor ($160,000 - $38,500) $121,500

Salary paid in cash       $33,200

Interest paid in cash   $1,890

Insurance policy purchased for cash $8,500

Total Disbursement (B) $165,090

Cash balance at the end (A - B) $235,010

The same is to be considered as a net income

All options that are given in the question is wrong

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Many new ventures focusing on craft beer have been launched. If the goal is to make a profit, perhaps it would have been a bette
klemol [59]

Answer:

a. Total rate variance = $1,660 Unfavorable

b. Total efficiency variance = $450 Unfavorable

Explanation:

From the question, we have:

Standard for hops = 20 pounds per barrel

Standard rate = Standard rate for hops = $13.00 per pound

Barrels of Hopalong beer produced = 40

Actual quantity = Actual pounds of hops used = 830 pounds

Standard quantity = Standard pounds of hops = Standard for hops * Barrels of Hopalong beer produced = 20 * 40 = 800 pounds

Actual rate = Actual cost of hops per pound = $15

Therefore, we have:

a. Compute the total rate variance for the past month

Total rate variance = (Actual rate - Standard rate) * Actual quantity = ($15 - $13) * 830 = $1,660 Unfavorable

The total rate variance of $1,660 is unfavorable because the Actual rate is greater than the Standard rate.

b. Compute the total efficiency variance for the past month

Total efficiency variance = (Actual quantity - Standard quantity) * Standard rate = (830 - 800) * $15 = $450 Unfavorable

The total efficiency variance of $450 is unfavorable because the Actual quantity is greater than the Standard quantity.

6 0
3 years ago
Assuming P≥0, suppose that a population develops according to the logistic equation ????P/????????=0.07P−0.00014P2 where ???? is
Natasha2012 [34]

Answer:

A complete description of the problem and solutions to each point are given below.

Explanation:

The Logistic Growth model of a population is defined as follows:

                                   dP/dt = kP (1 - P/M) (1)

Where:

dP/dt is the population growth rate.

k is the maximal individual growth rate for a given population

P is the number of individual in the population

M= carrying capacity of the population.

In the problem this first order derivative ecuation is given by

                               dP/dt= 0,07P - 0,00014P² (2)

So, we can factorize ecuation (1) and compare it with (2) to find the carryng capacity and k value (questions 1 and 2).

                                        kP (1 - P/M) = 0,07P - 0,00014P²

                                        kP - (k/M)P² = 0,07P - 0,00014P²

Here kP = 0,07P ⇒ k = 0,07 (answer to question 2)

Then, (k/M)P² = 0,00014P²⇒ (k/M) = 0,00014 and given that k= 0,07

⇒ 0,07/M = 0,00014 ⇒ M = 0,07/0,00014 ⇒ M=500 (answer to question 1)

Finally to find for which values of P is the population increasing/decreasing, we have to find the values at which dP/dt is zero. Analyzing the equation as a quadratic function (applying Baskara´s equation) we find that the values at which dP/dt is zero are P= 0 and P = -1.

x = [-0,07 ± √(0,07²)]/ 0,14 ⇒ x=  [-0,07 ± 0,07)]/ 0,14 ⇒ x = 0 and x= -1.

Then the vertex here is P = -0,5.

Now we can state that for P greater than - 0,5 the population is decreasimg (question 4), while for values from -∞ to - 0,5 the population is increasing (question 3).

Summarizing, given the first order derivative, the carrying capacity of the population is 500, the value of k is 0,07, the values of P for which dP/dt is positive (incresing population) are those comprised in the range (-∞, -0,5) and those for which the population is decreasing are (-0,5,∞).

3 0
3 years ago
What are the different ways a business can merge
Artemon [7]

What type of skew is observed in this histogram?

<span><span> symmetry</span><span> zero skew </span><span> negative skew</span><span> positive skew 
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7 0
3 years ago
Ten years ago, Lucas Inc. earned $0.50 per share. Its earnings this year were $5.00. What was the growth rate in earnings per sh
liberstina [14]

Answer:

25.89%

Explanation:

With regards to the above information, initial earning = $0.50

Final earnings = $5.0

Number of periods = 10 years

We can formulate the above into an equation, which will now be:

$5.00 = $0.5 ( 1 + rate )^ 10

We can simplify furthermore.

1 + rate ^ 10 = 5 / 0.5

1 + rate ^ 10 = 10

1 + rate ^ 10 = 10^1/10

1 + rate = 10 ^ 0.1

1 t rate = 1.2589

rate = 1.2589 - 1

rate = 0.2589

rate = 25.89%

Therefore, the growth rate in earnings per share (EPS) over the 10 year period is 25.89% .

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3 years ago
Which scenario best demonstrates the function of money as a measure of value?
Musya8 [376]
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7 0
3 years ago
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