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ZanzabumX [31]
3 years ago
14

f as a function of x is equal to the square root of quantity x plus six; g(x) = 8x - 10 Find f(g(x)).

Mathematics
1 answer:
rosijanka [135]3 years ago
6 0

Answer: The value of f(g(x)) is 2\sqrt{2x-1}

Step-by-step explanation:

Since we have given that

g(x)=8x-10

and f(x) is given by

f(x)=\sqrt{x+6}

We need to find the fog(x) i.e. f(g(x)).

So, it becomes,

f(g(x))=f(8x-10)\\\\f(g(x))=\sqrt{8x-10+6}\\\\f(g(x))=\sqrt{8x-4}\\\\f(g(x))=\sqrt{4(2x-1)}\\\\f(g(x))=2\sqrt{2x-1}

Hence, the value of f(g(x)) is 2\sqrt{2x-1}

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3 years ago
—— ——
blsea [12.9K]

Given: NQ = NT , QS Bisect NT(∴ NS=ST ) , TV Bisects QN (∴ NV=VQ )

To Prove: QS=TV

Proof: In ΔNQT

NQ=NT

\frac{1}{2}NQ=\frac{1}{2}NT

∴ VQ=ST

In a isosceles triangle, If two sides are equal then their opposites angles are equal.

∴ ∠NQT=∠NTQ       ( ∵ NQ=NT)

In ΔQST and TVQ

ST=VQ                    (sides of isosceles triangle)

∠NQT=∠NTQ          (Prove above)

QT=TQ                    (Common)

So, ΔQST ≅ TVQ  by SAS congruence property

∴ QS=TV  (CPCT)

CPCT: Congruent part of congruence triangles.

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2 years ago
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So, the area is

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2 years ago
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Answer:

1/64

Step-by-step explanation:

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