Answer:
The correct answer is A. and B.
Step-by-step explanation:
If it's flipped over to the other side, it will still be the same shape and the same size.
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Answer:
Option C) The two quantities are equal.
Step-by-step explanation:
We are given the following in the question:
n is a negative integer and p is a positive integer.
Quantity A: The product of the integers from n to p
Quantity B: 0
Quantity A is the product of integers from n to p. Since all the integers from n to p will include zero between them, thus the product of all the integers from n to p will be zero.
The product takes place in the following manner:
Thus, both the quantities are equal.
Option C) The two quantities are equal.
Answer:
(-1, -1) Let me know if the explanation didn't make sense.
Step-by-step explanation:
If we graph the three points we can see what looks like a quadrilateral's upper right portion, so we need a point in the lower left. This means M is only connected to N here and P is only connected to N. So we want to find the slope of these two lines.
MN is easy since their y values are the same, the slope is 0.
NP we just use the slope formula so (y2-y1)/(x2-x1) = (-1-3)/(5-4) = -4.
So now we want a line from point M with a slope of -4 to intersect with a line from point P with a slope of 0. To find these lines weuse point slope form for those two points. The formula for point slope form is y - y1 = m(x-x1)
y-3 = -4(x+2) -> y = -4x-5
y+1 = 0(x-5) -> y = -1
So now we want these two to intersect. We just set them equal to each other.
-1 = -4x -5 -> -1 = x
So this gives us our x value. Now we can plug that into either function to find the y value. This is super easy of we use y = -1 because all y values in this are -1, so the point Q is (-1, -1)
Answer:
$21.55
Step-by-step explanation:
21.50 + 44.95 + 12 = $78.45
100 - 78.45= $21.55
2/440 Original Mathematical Expression.
1/220 Divide numerator and denominator by 2.
This equals . . .
0.004545454545 repeating
(I just plugged 1/220 into calculator)
Final Answer: 1/220 or 0.004545454545 repeating
