All categories

3 years ago

Write the equation in slope intercept form with a slope of 3/4 and passes through (-4,-5)

Mathematics

1 answer:

attashe74 [19]3 years ago

7 0

Answer:Use the slope −2 and the point (−4,−5) to find the y-intercept.

y=mx+b

⇒−5=(−2×−4)+b

⇒−5=8+b

⇒b=−13

Write the equation in slope intercept form as:

y=mx+b

⇒y=(−2)x−13

Hence, the equation of the line is y=−2x−13.

Step-by-step explanation:

Please make me brainliest :)

You might be interested in

tim brought a car 25000 and it depreciation $350 per year. What is the value of the car after 6 years?

blondinia [14]

Answer:

22900

Step-by-step explanation:

multiply 350 by 6 and get 2100

subtract 2100 from 25k and get 22900

6 0

4 years ago

Read 2 more answers

-(18+4x)=8 hope you can help

Step2247 [10]

-1(18+4x)=8
Then you distribute
-18-4x=8
-4x=26
X= -6.5

4 0

4 years ago

Read 2 more answers

Please help me still bad at ratio :)

Sholpan [36]

Answer:

111 grams

Step-by-step explanation:

fruit: yoghurt: total

2 : 3 : 2+3=5

The total mass is 185

Divide 185/5 = 37

Multiply each number by 37

fruit: yoghurt: total

2*37 : 3 *37 : 5*37

74 111 185

The mass of the yoghurt is 111

3 0

4 years ago

Please help!! thank you.

Zina [86]

(A) Product of $-2x^{3}+x-5$ and $x^{3}-3x-4$ is:

$(-2x^{3}+x-5)(x^{3}-3x-4)$

$=-2x^{3}(x^{3}-3x-4)+x(x^{3}-3x-4)-5(x^{3}-3x-4)$

$=(-2x^{3})(x^{3})+(-2x^{3})(-3x)+(-2x^{3})(-4)+x(x^{3})+(x)(-3x)+(x)(-4)+(-5)(x^{3})+(-5)(-3x)+(-5)(-4)$

$=-2x^{6}+6x^{4}+8x^{3}+x^{4}-3x^{2}-4x-5x^{3}+15x+20$

$=-2x^{6}+6x^{4}+x^{4}+ 8x^{3}-5x^{3}-3x^{2}-4x+15x+20$

$=-2x^{6}+7x^{4}+3x^{3}-3x^{2}+11x+20$

(B) Yes.

Product of $-2x^{3}+x-5$ and $x^{3}-3x-4$ = Product of $x^{3}-3x-4$ and $-2x^{3}+x-5$ because multiplication is commutative.

Commutative Property of multiplication says that a.b = b.a.

Thus, multiplication is same irrespective of the order of two numbers.

5 0

3 years ago

adiocarbon dating of blackened grains from the site of ancient Jericho provides a date of 1315 BC ± 13 years for the fall of the

Zigmanuir [339]

Answer:

$\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659$ and $\left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661$

Step-by-step explanation:

The equation of the isotope decay is:

$\frac{m(t)}{m_{o}} = e^{-\frac{t}{\tau} }$

14-Carbon has a half-life of 5568 years, the time constant of the isotope is:

$\tau = \frac{5568\,years}{\ln 2}$

$\tau \approx 8032.926\,years$

The decay time is:

$t = 1315\,years + 2007\,years \pm 13\,years$ (There is no a year 0 in chronology).

$t = 3335 \pm 13\,years$

Lastly, the relative amount is estimated by direct substitution:

$\frac{m(t)}{m_{o}} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\mp\frac{13\,years}{8032.926\,years} }$

$\left(\frac{m(t)}{m_{o}} \right)_{min} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{-\frac{13\,years}{8032.926\,years} }$

$\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659$

$\left(\frac{m(t)}{m_{o}} \right)_{max} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\frac{13\,years}{8032.926\,years} }$

$\left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661$

4 0

3 years ago