A square and a rectangle have the same perimeter. The square has a side length of 8x units. The rectangle has a length of (10x+8 ) units and a width of 10 units. What will be the perimeter of either the rectangle and the square?
1 answer:
Well we know that the perimeters are equal so: Psquare = Prectangle we know perimeter for square is the 4 sides of same lengths added up or 4*s the perimeter of a rectangle is the then4 sides with 2 being equal added up so 2*L + 2*W we know that a square side equAls s and it says that s=8x. So: Psqu = 4 * (8x) (substitute 8x for s) we know that the rectangle L =10x + 8 and W =10. So Prect = 2 *(10x + 8) + 2 * (10) we know : Prect = Psqu so: 4 * (8x) =2 *(10x + 8) + 2 * (10) 32x = 20x + 16 + 20 12x = 36 x = 3 So if x equals 3 we can sub x in for square perimeter Psqu = 4 *(8 * 3) P = 4 * 24 P = 96 we can check this with rectangle perimeter P = 2 *(10 * 3 + 8) + 2 *10 P = 2 * 38 + 20 P = 96
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