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Finger [1]
4 years ago
8

A square and a rectangle have the same perimeter. The square has a side length of 8x units. The rectangle has a length of (10x+8

) units and a width of 10 units. What will be the perimeter of either the rectangle and the square?
Mathematics
1 answer:
Elden [556K]4 years ago
7 0
Well we know that the perimeters are equal so:
Psquare = Prectangle

we know perimeter for square is the 4 sides of same lengths added up or 4*s

the perimeter of a rectangle is the then4 sides with 2 being equal added up so 2*L + 2*W

we know that a square side equAls s and it says that s=8x. So:
Psqu = 4 * (8x) (substitute 8x for s)

we know that the rectangle L =10x + 8 and W =10. So
Prect = 2 *(10x + 8) + 2 * (10)

we know :
Prect = Psqu so:
4 * (8x) =2 *(10x + 8) + 2 * (10)
32x = 20x + 16 + 20
12x = 36
x = 3

So if x equals 3 we can sub x in for square perimeter
Psqu = 4 *(8 * 3)
P = 4 * 24
P = 96

we can check this with rectangle perimeter
P = 2 *(10 * 3 + 8) + 2 *10
P = 2 * 38 + 20
P = 96
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Answer:

I'm assuming you don't want to paint the floor.

1220

Step-by-step explanation:

25 * 8 = 200. Now we multiply that by 2 to get 400. Those are the 2 walls.

The ceiling is 25 * 20 = 500.

20 * 8 = 160. Now we multiply that by 2 to get 320. Those are the 2 walls.

500 + 400 + 320 = 1220

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4 years ago
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Maurinko [17]
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3 years ago
Martin wants to use coordinate geometry to prove that the opposite sides of
Vinil7 [7]

Answer:

Option (B)

Step-by-step explanation:

Coordinates of the vertices of the rectangle were A(0, 0), B(a, 0), C(a, b) and D(0, b)

Formula to determine the distance between two points with the vertices (x, y) and (x', y') is,

d = \sqrt{(x-x')^2+(y-y')^2}

For the length of AD,

AD = \sqrt{(0-0)^2+(b-0)^2}

     = \sqrt{b^2}

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Therefore, Option (B) will be the answer.

5 0
4 years ago
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8 0
3 years ago
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a television on sale for 1/4 off original price. Original price is 120 more then sale price. What is original price of tv
agasfer [191]

Answer:

Original Price = 160

Sale Price =40

Step-by-step explanation:

Let Original Price be x and Sale Price be y

y=1/4 of x   (Equation 1)

x=120+y     (Equation 2)

Put value of x from equation 2 in equation 1

y= (1/4)*(120+y)

y=120/4 + y/4

y-y/4=30

3y/4=30

y=30*4/3

y=40

Put value of y in Equation 2

x=120+40

x=160

4 0
3 years ago
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