For the 1st hour the cost is $50 whatever is the duration (providing it's 1 hour max.
From one hour and onward the cost becomes an additional $25 per quater of an hour.
If y is the cost and x the number of hours, then the equation becomes :
y =50 + 0.25.x or y =1/4x + 50
Answer:
<h2> 105 tickets</h2>
Step-by-step explanation:
To solve this problem we need to model an equation to represent the situation first.
the goal is to archive $7500 in the even, bearing in mind that there is a cost of $375 fee for rent, we need to put this amount into consideration
let the number of tickets be x
so
75x-375>=7500--------1
Equation 1 above is a good model for the equation
we can now solve for x to determine the number of tickets to be sold to archive the aim
75x-375>=7500--------1
75x>=7500+375
75x>=7875
divide both sides by 75 we have
x>=7875/75
x>=105 tickets
so they must sell a total of 105 tickets and above to meet the target of $7500 with the rent inclusive
Answer:
7x^2+5x
Step-by-step explanation:
Given
Polynomial 1: 9x^2+8x
Polynomial 2: 2x^2+3x
We have to find subtraction of both
So,
9x^2+8x - (2x^2+3x)
First of all the brackets will be eliminated by multilying the minus sign
9x^2+8x-2x^2-3x
The terms with same power of variable will be written together
9x^2-2x^2+8x-3x
=7x^2+5x ..
