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Kobotan [32]
3 years ago
10

ANSWER ME PLS BRAINLIEST What is the average number of points scored in the 15 games played?

Mathematics
2 answers:
Ira Lisetskai [31]3 years ago
5 0

Answer:

6

Step-by-step explanation:

daser333 [38]3 years ago
4 0

Answer:

the answer is 6

Step-by-step explanation: LOgic

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the second of three numbers is 1 less than the first. The third number is 5 less than twice the second. If the number exceeds th
dalvyx [7]
60-sixty is the answer
7 0
3 years ago
Yep here we go again:
vesna_86 [32]

Answer:

100 - 35 = 65 %

Step-by-step explanation:

you need to do math by 100 % and 35% woth a minus and it will become 65

5 0
3 years ago
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How do you write 2x minus 16 in words phares​
Mars2501 [29]

Sixteen is less than twice a number.

7 0
4 years ago
How do i solve the circumference with the diameter of 1.3?
Contact [7]

Answer:

Inputs:

Radius (r):

0.65

or

Diameter (d):

1.3

or

Area (A):

1.327

Unit of Lenght:

centimeter

Calculate Circumference

Result:

The circumference of a circle with diameter 1.3 is 4.084(*)

Formulas:

r = 0.65

d = 1.3

C = 4.08

C = 2·π·r C = π·d C = √4·π·A π = 3.1415

A = area of the circle

C = circumference or perimeter

r = radius, d = diameter

Step-by-step Solution:

Circumference of a cicle in terms of radius:

Circumference = 2·π·r = 2·3.14·0.65 = 4.09(*)

In terms of diameter:

Circumference = π·d = 3.14·1.3 = 4.08(*)

In terms of area:

Circumference C = √4·π·A = √4·π·1.33 = 4.09(*)

(*) 4.084 cm exactly or limited to de precision of this calculator (13 decimal places).

Note: for simplicity, the operations above were rounded to 2 decimal places and π was rounded to 3.14.

A circumference of 4.084 centimeters is equal to:

4.084E-5 kilometers (km)

0.04084 meters (m)

40.84 millimeters (mm)

2.53768E-5 miles (mi)

0.0446632 yards (yd)

0.13399 feet (ft)

1.60787 inches (in)

8 0
3 years ago
Read 2 more answers
The half-life of radioactive actinium (^227 Ac) is 22 years. How much will remain after 15 years? Find R first.
Llana [10]
Use the formula below.

Let A_0 = 1 because you just want to know the percentage left. Usually that's the initial amount.

t = 15, the number of years past. n = 22, the half-life.

A=A_0(0.5)^{\frac{t}{n}} \\  \\ A=0.5^{\frac{15}{22}} \\  \\ A=0.62 = 62\%
5 0
3 years ago
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