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love history [14]
3 years ago
7

PLEASE HELP ME FIND X please I really need help

Mathematics
2 answers:
Liono4ka [1.6K]3 years ago
7 0

Answer:

is this a multiple-choice type thing or type-in? If multiple-choice, what answers are given?

Step-by-step explanation:

sladkih [1.3K]3 years ago
4 0

Answer:

HI

Step-by-step explanation:

BRAINLY POINTS FOR DAYYYYSSSS!!!!

>:(]

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What are the domain,range,and asymptote of h(x)=2 to the power of x+2
jeka57 [31]

Domain: (-infinity,infinity)


Range: (0, infinity)


The asymptote is at 0

8 0
3 years ago
Write a linear function that relates y to x
Sliva [168]

Answer:

y = x -2

Step-by-step explanation:

Slope is 1, y-intercept is (0,-2)

8 0
3 years ago
Read 2 more answers
Krissy ran three miles one morning she ran the first mile in 11. 74 minutes the second mile in 11. 26 minutes in the third mile
Snowcat [4.5K]

<u>35.12 miles </u><u>is the total number of minutes that it took krissy to run these three miles.</u>

What is a simple definition of time?

The measured or measurable period during which an action, process, or condition exists or continues : duration. b : a nonspatial continuum that is measured in terms of events which succeed one another from past through present to future.

Krissy ran three miles one morning she ran the first mile in time 1 = 11.74

Krissy ran three miles one morning she ran the first mile in time 2 = 11.26

Krissy ran three miles one morning she ran the first mile in time 3 = 12.12          

To get total time , we have to add all the time 1,2,3

Total time = Time1 + Time2 + Time3

                  = 11.74 + 11.26 + 12.12

Total Time =  35.12 <u>miles</u>

Learn more about time

brainly.com/question/10932008

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3 0
2 years ago
Read 2 more answers
Find the form of the general solution of y^(4)(x) - n^2y''(x)=g(x)
Dennis_Churaev [7]

The differential equation

y^{(4)}-n^2y'' = g(x)

has characteristic equation

<em>r</em> ⁴ - <em>n </em>² <em>r</em> ² = <em>r</em> ² (<em>r</em> ² - <em>n </em>²) = <em>r</em> ² (<em>r</em> - <em>n</em>) (<em>r</em> + <em>n</em>) = 0

with roots <em>r</em> = 0 (multiplicity 2), <em>r</em> = -1, and <em>r</em> = 1, so the characteristic solution is

y_c=C_1+C_2x+C_3e^{-nx}+C_4e^{nx}

For the non-homogeneous equation, reduce the order by substituting <em>u(x)</em> = <em>y''(x)</em>, so that <em>u''(x)</em> is the 4th derivative of <em>y</em>, and

u''-n^2u = g(x)

Solve for <em>u</em> by using the method of variation of parameters. Note that the characteristic equation now only admits the two exponential solutions found earlier; I denote them by <em>u₁ </em>and <em>u₂</em>. Now we look for a particular solution of the form

u_p = u_1z_1 + u_2z_2

where

\displaystyle z_1(x) = -\int\frac{u_2(x)g(x)}{W(u_1(x),u_2(x))}\,\mathrm dx

\displaystyle z_2(x) = \int\frac{u_1(x)g(x)}{W(u_1(x),u_2(x))}\,\mathrm dx

where <em>W</em> (<em>u₁</em>, <em>u₂</em>) is the Wronskian of <em>u₁ </em>and <em>u₂</em>. We have

W(u_1(x),u_2(x)) = \begin{vmatrix}e^{-nx}&e^{nx}\\-ne^{-nx}&ne^{nx}\end{vmatrix} = 2n

and so

\displaystyle z_1(x) = -\frac1{2n}\int e^{nx}g(x)\,\mathrm dx

\displaystyle z_2(x) = \frac1{2n}\int e^{-nx}g(x)\,\mathrm dx

So we have

\displaystyle u_p = -\frac1{2n}e^{-nx}\int_0^x e^{n\xi}g(\xi)\,\mathrm d\xi + \frac1{2n}e^{nx}\int_0^xe^{-n\xi}g(\xi)\,\mathrm d\xi

and hence

u(x)=C_1e^{-nx}+C_2e^{nx}+u_p(x)

Finally, integrate both sides twice to solve for <em>y</em> :

\displaystyle y(x)=C_1+C_2x+C_3e^{-nx}+C_4e^{nx}+\int_0^x\int_0^\omega u_p(\xi)\,\mathrm d\xi\,\mathrm d\omega

7 0
3 years ago
Find the coordinates of the missing endpoint if m is the midpoint of xy
Andre45 [30]
I hope this helps you

5 0
3 years ago
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