We know that
If the scalar product of two vectors<span> is zero, both vectors are </span><span>orthogonal
</span><span>A. (-2,5)
</span>(-2,5)*(1,5)-------> -2*1+5*5=23-----------> <span>are not orthogonal
</span><span>B. (10,-2)
</span>(10,-2)*(1,5)-------> 10*1-2*5=0-----------> are orthogonal
<span>C. (-1,-5)
</span>(-1,-5)*(1,5)-------> -1*1-5*5=-26-----------> are not orthogonal
<span>D. (-5,1)
</span>(-5,1)*(1,5)-------> -5*1+1*5=0-----------> are orthogonal
the answer is
B. (10,-2) and D. (-5,1) are orthogonal to (1,5)
The correct answer is:
2u-v=7(5i-3j)
Therefore, 5, and 3 go inside the box.
Answer:
x, StartFraction x Over 2 EndFraction, StartFraction x Over 4 EndFraction, StartFraction x Over 8 EndFraction, ellipsis
Step-by-step explanation:
The tenth place is the first number to the right of a decimal. To determine if you're rounding or not, check the hundred's place, 2 numbers to the right of a decimal, for 5 or higher. If it's .45, round to .5, if it's .44, round to .4
Your answer is 524.5, which is B.)
Answer:
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Explanation:
Simulate (build a table) the growing of the number of pennies for some nights to figure out the pattern:
First night: 1 penny = 2⁰
Second night: 1 × 2 pennies = 2¹
Third night: 2 × 2 = 2²
Fourth nigth: 2² × 2 = 2³
nth night: 2ⁿ⁻¹
You want 2ⁿ⁻¹ ≥ 2,000,000,000
Which you solve in this way:
- n-1 log (2) ≥ log (2,000,000,000)
- n - 1 ≥ log (2,000,000,000) / log (2)
Since n is number of days, it is an integer number, so n ≥ 32.
Hence, she will have a total of more than $ 2 billion after 32 days.
You can prove that by calculating 2³² = 2,147,483,648.
