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IRISSAK [1]
3 years ago
9

Alpaca Corporation had revenues of $250,000 in its first year of operations. The company has not collected on $18,900 of its sal

es and still owes $27,000 on $96,000 of merchandise it purchased. The company had no inventory on hand at the end of the year. The company paid $12,700 in salaries. Owners invested $14,000 in the business and $14,000 was borrowed on a five-year note. The company paid $3,800 in interest that was the amount owed for the year, and paid $7,800 for a two-year insurance policy on the first day of business. Alpaca has an effective income tax rate of 40%. (Assume taxes are paid in the same year). Compute the cash balance at the end of the first year for Alpaca Corporation.
Business
1 answer:
Sever21 [200]3 years ago
4 0

Answer:

$84,360.00  

Explanation:

The cash balance at the end of the year is simply total cash receipts minus total cash payments which is further analyzed below:

Cash receipt from sales=total sales-accounts receivable=$250,000-$18,900=$ 231,100.00  

Cash paid for merchandise purchase=purchases-accounts payable=$96,000-$27,000=$69,000

Salaries paid     $12,700

Cash from  owners is $14,000

cash from borrowing is $14,000

interest paid is $3800

insurance paid is $7,800

Tax paid=(sales-purchases-salaries paid-insurance cost(one year)-interest paid)*tax rate

insurance for one year=$7800*1/2=$3,900

tax paid=($250,000-$96,000-$12,700-$3,800-$3,900)*40%=$53440

Cash balance=$231,100-$69,000-$12,700+$14,000-$14,000-$3800-$7800-$53440=$84,360.00  

 

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Appellate courts do not have to hear all of the cases they are presented.<br> True<br> False
frutty [35]
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3 years ago
Aliyah purchased Verizon Communications stock in April 2015 for $48.90 per share. She sold the stock one-year later for $54.01 p
soldier1979 [14.2K]

Answer:

Capital Gains Yield = 10.45%

Explanation:

The capitals gain yield represents the percentage appreciation or increase in the value of an investment. It is simply calculated by calculating the increase in the value of an investment or stock/bond and divide it by its initial cost.

The formula for CG Yield is,

CG Yield = (P1 - P0) / P0

Where,

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Thus CG Yield = (54.01 - 48.9) / 48.9 = 0.10449 pr 10.449%

5 0
3 years ago
Each machine must be run by one of 19 cross-trained workers who are each available 35 hours per week. The plant has 10 type 1 ma
Mrac [35]

Answer:

The Linear programming model is given as below

Profit Function: P=90X+120Y+150Z

Constraints:

2X+2Y+Z\leq 400

3X+4Y+6Z\leq 240

4X+6Y+5Z\leq 320

\dfrac{2X+2Y+Z}{40}\leq 10

\dfrac{3X+4Y+6Z}{40}\leq 6

\dfrac{4X+6Y+5Z}{40}\leq 8

\dfrac{2X+2Y+Z}{35}+\dfrac{3X+4Y+6Z}{35}+\dfrac{4X+6Y+5Z}{35}\leq 19

Explanation:

As the question is not complete, the complete question is found online and is attached herewith.

Let the number of product 1 to be produced is X, that of product 2 is Y and product 3 is Z

so  the maximizing function is the profit function which is given as

P=90X+120Y+150Z

Now as the number of hours in a week are 40 and there are a total of 10 type 1 machines so the total number of machine 1 hours are 40*10=400 hours

As from the given table product 1 uses 2 machine hours of machine 1, product 2 uses 2 machine hours of machine 1 and product 3 uses 1 hour of machine 1 so

2X+2Y+Z\leq 400

Now as the number of hours in a week are 40 and there are a total of 6 type 2 machines so the total number of machine 2 hours are 40*6=240 hours

As from the given table product 1 uses 3 machine hours of machine 2, product 2 uses 4 machine hours of machine 2 and product 3 uses 6 hour of machine 2 so

3X+4Y+6Z\leq 240

Now as the number of hours in a week are 40 and there are a total of 8 type 3 machines so the total number of machine 3 hours are 40*8=320 hours

As from the given table product 1 uses 4 machine hours of machine 3, product 2 uses 6 machine hours of machine 3 and product 3 uses 5 hour of machine 3 so

4X+6Y+5Z\leq 320

Now as the machine 1 is used as 2X+2Y+Z in a week and the week is of 40 hours so the number of machines to be used are given as

\dfrac{2X+2Y+Z}{40}\leq 10

Now as the machine 2 is used as 3X+4Y+6Z in a week and the week is of 40 hours so the number of machines to be used are given as

\dfrac{3X+4Y+6Z}{40}\leq 6

Now as the machine 3 is used as 4X+6Y+5Z in a week and the week is of 40 hours so the number of machines to be used are given as

\dfrac{4X+6Y+5Z}{40}\leq 8

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\dfrac{2X+2Y+Z}{35}

That of machine 2 is given as

\dfrac{3X+4Y+6Z}{35}

That of machine 3 is given as

\dfrac{4X+6Y+5Z}{35}

As the total number of workers is 19 so the constraint is given as

\dfrac{2X+2Y+Z}{35}+\dfrac{3X+4Y+6Z}{35}+\dfrac{4X+6Y+5Z}{35}\leq 19

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Profit Function: P=90X+120Y+150Z

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2X+2Y+Z\leq 400

3X+4Y+6Z\leq 240

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cupoosta [38]

Through employment and engaging communities thru comprehensive business models, the private sector can play a significant role in poverty alleviation.

 

As it brings community members into the value chain thus making it a more sustainable relationship, this approach is makes it different from just social corporate responsibility.

4 0
3 years ago
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