<span>If you plug in 0, you get the indeterminate form 0/0. You can, therefore, apply L'Hopital's Rule to get the limit as h approaches 0 of e^(2+h),
which is just e^2.
</span><span><span><span>[e^(<span>2+h) </span></span>− <span>e^2]/</span></span>h </span>= [<span><span><span>e^2</span>(<span>e^h</span>−1)]/</span>h
</span><span>so in the limit, as h goes to 0, you'll notice that the numerator and denominator each go to zero (e^h goes to 1, and so e^h-1 goes to zero). This means the form is 'indeterminate' (here, 0/0), so we may use L'Hoptial's rule:
</span><span>
=<span>e^2</span></span>
Answer:
155
Step-by-step explanation:
= (15)x10+5
= 150+5
= 155
Yes, -0.5 is an integer because it is a negative number. Any number that is positive or negative is an integer.
Answer:
15 hours, or B
Step-by-step explanation:
6 men - 10
12 men - 5
4 men - 15
<em>Please mark as brainliest</em>
