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galina1969 [7]
3 years ago
10

Angelique draws a triangle GHK. If

Mathematics
1 answer:
kap26 [50]3 years ago
5 0
Where is the rest of the problem?



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Determine whether the given value is a solution of the equation.
nlexa [21]

Answer:

16 is not the solution to the equation

Step-by-step explanation:

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3 years ago
12/18 ATB - Review question -<br> Evaluate 18x + 75 when x= 8.
boyakko [2]

Answer:

solution

x=8

so,

18 .8 +75

144 +75

219

7 0
3 years ago
Ignore the decimal pls
Tresset [83]
So if 18 + x =43, then what you need to do is

18 + x =43
-18 -18
——————
x = 25

because whatever you do to one side, you need to do to the other
5 0
3 years ago
Which of the given values are in the interval (-3,1]?
Vladimir [108]

The values coming in the interval (-3,1] are -2, -1, 0, and 1.

<h3>What is defined as the term interval notations?</h3>
  • An interval is represented on a number line using interval notation. In all other sayings, it is a method of writing real number line subsets.
  • An interval is made up of numbers that fall between two specific data set.
  • Intervals can be categorized according to the numbers in the set.
  1. Interval Open: The endpoints of a inequality are not included in this type of interval.
  2. Interval Closure; The endpoints of a inequality are included in this type of interval.
  3. Interval with Half-Open Doors: This interval contains only one of inequality's endpoints.

The given interval notation is;

(-3,1], it is the case of half open half close.

-3 comes with the open interval, it means its value will not be included in the interval.

1 is with the closed interval, it means its value will be included in the interval.

Thus, the values lying between the interval (-3, 1] are  -2, -1, 0, and 1.

To know more about the interval notations, here

brainly.com/question/16768997

#SPJ10

6 0
1 year ago
D= kA [T2 - T1 / L] Solve for T1
mel-nik [20]
d=\dfrac{k_A(T_2-T_1)}{T}\ \ \ \ |multiply\ both\ sides\ by\ T\\\\k_A(T_2-T_1)=dT\ \ \ \ |divide\ both\ sides\ by\ k_A\\\\T_2-T_1=\dfrac{dT}{k_A}\ \ \ \ |subtract\ T_2\ from\ both\ sides\\\\-T_1=\dfrac{dT}{k_A}-T_2\ \ \ \ \ |change\ signs\\\\\boxed{T_1=T_2-\frac{dT}{k_A}}
5 0
3 years ago
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