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3 years ago

The complement of angle A is 38 degrees more than angle A

2 answers:

ozzi3 years ago

8 0

I assume that you want the measurement of angle A
A + (A + 38) = 90
angle A + (38 more than angle a) = are complementary
2A = 52
A = 26

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mafiozo [28]3 years ago

6 0

The complement of < A......90 - A

90 - A = A + 38
-A -A = 38 - 90
-2A = - 52
A = -52/-2
A = 26

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What are the solutions to the equation |x – 10| – 4 = 2x?

Yuliya22 [10]

|x – 10| – 4 = 2x

x - 10 - 4 = 2x

x - 14 = 2x

x - 2x = 14

-x = 14

x = -14

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2 years ago

What is the solution to the equation

Dafna11 [192]

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therefore
$D:x\in\left< -\dfrac{5}{4};\ 6\right>$

$\sqrt{4t+5}=3-\sqrt{t+5}\ \ \ |^2\\\\(\sqrt{4t+5})^2=(3-\sqrt{t+5})^2\ \ \ |use:(a-b)^2=a^2-2ab+b^2\\\\4t+5=3^2-2\cdot3\cdot\sqrt{t+5}+(\sqrt{t+5})^2\\\\4t+5=9-6\sqrt{t+5}+t+5\ \ \ \ |-t\\\\3t+5=14-6\sqrt{t+5}\ \ \ \ |-14\\\\3t-9=-6\sqrt{t+5}\ \ \ \ |change\ signs$
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7 0

3 years ago

Read 2 more answers

There are two parking garages in beacon falls . Garage a charges $7.00 to park for the first 2 hours ,and each additional hour c

Julli [10]

Answer

Find out the number of hours when the cost of parking at both garages will be the same.

To prove

As given

There are two parking garages in beacon falls .

As given

Let us assume that the y is representing the cost of parking at both garages will be the same.

The total number of hours is represented by the x.

First case

Garage a charges $7.00 to park for the first 2 hours ,and each additional hour costs $3.00 .

As garage charges $7.00 for the first 2 hours so the remaning hours are (x -2)

Than the equation becomes

y = 3.00 (x -2) + 7.00

written in the simple form

y = 3x - 6 +7

y = 3x + 1

Second case

Garage b charges $3.25 per hour to park.

than the equation becomes

y = 3.25x

Compare both the equations

3x +1 = 3.25x

3.25x -3x = 1

.25x = 1

$x = \frac{1}{.25}$

x = 4hours

Therefore in the 4 hours the cost of parking at both garages will be the same.

3 0

3 years ago

Answer both please, the topic is linear inequalities, and please explain it to me.

Bogdan [553]

Question 1 solution:
You have two unknowns here:

Let the Water current speed = W

Let Rita's average speed = R

We are given two situations, where we can form two equations, and therefore solve for the two unknowns, W, R:

Part 1) W→ , R←(against current, upstream)
If Rita is paddling at 2mi/hr against the current, this means that the current is trying to slow her down. If you look at the direction of the water, it is "opposing" Rita, it is "opposite", therefore, our equation must have a negative sign for water:

R–W=2 - equation 1

Part 2) W→ , R→(with current)
Therefore, R+W=3 - equation 2

From equation 1, W=R-2,
Substitute into equation 2.
R+(R–2)=3
2R=5
R=5/2mi/hr

So when W=0 (still), R=5/2mi/hr

Finding the water speed using the same rearranging and substituting process:

1... R=2+W
2... (2+W)+W=3
2W=1
W=1/2mi/hr

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3 years ago

Find the area of the following composite figure please

telo118 [61]

Step-by-step explanation:

answer is in photo above

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2 years ago