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Sphinxa [80]
3 years ago
8

Which of the following ratios correctly describes the tangent function? a. opp/adj b. opp/hyp c. adj/hyp

Mathematics
2 answers:
Elena L [17]3 years ago
7 0
A. opp/adj because the the tangent is the hypotenuse so it eliminates all equations that require the hypotenuse.
Lera25 [3.4K]3 years ago
5 0

Answer: a.opp/adj


Step-by-step explanation:

The tangent function, along with sine and cosine, is one of the three most common trigonometric functions.

For any given angle x

\tan\ x=\frac{\sin\ x}{\cos\ x}=\frac{\frac{\text{side opposite to x}}{\text{hypotenuse}}}{\frac{\text{side adjacent to x}}{\text{hypotenuse}}}\\\Rightarrow\tan\ x=\frac{\text{side opposite to x}}{\text{side adjacent to x}}

thus, opp/adj  correctly describes the tangent function.



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Find a point on the curve x^3+y^3=11xy other than the origin at which the tangent line is horizontal.
attashe74 [19]

Compute the derivative dy/dx using the power, product, and chain rules. Given

x³ + y³ = 11xy

differentiate both sides with respect to x to get

3x² + 3y² dy/dx = 11y + 11x dy/dx

Solve for dy/dx :

(3y² - 11x) dy/dx = 11y - 3x²

dy/dx = (11y - 3x²)/(3y² - 11x)

The tangent line to the curve is horizontal when the slope dy/dx = 0; this happens when

11y - 3x² = 0

or

y = 3/11 x²

(provided that 3y² - 11x ≠ 0)

Substitute y into into the original equation:

x³ + (3/11 x²)³ = 11x (3/11 x²)

x³ + (3/11)³ x⁶ = 3x³

(3/11)³ x⁶ - 2x³ = 0

x³ ((3/11)³ x³ - 2) = 0

One (actually three) of the solutions is x = 0, which corresponds to the origin (0,0). This leaves us with

(3/11)³ x³ - 2 = 0

(3/11 x)³ - 2 = 0

(3/11 x)³ = 2

3/11 x = ³√2

x = (11•³√2)/3

Solving for y gives

y = 3/11 x²

y = 3/11 ((11•³√2)/3)²

y = (11•³√4)/3

So the only other point where the tangent line is horizontal is ((11•³√2)/3, (11•³√4)/3).

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Step-by-step explanation:

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hope this helps u

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