Answer:
a
x
2
+
b
x
+
c
=
0
the two roots of the equation take the form
x
1
,
2
=
−
b
±
√
b
2
−
4
a
c
2
a
So, start by adding
−
5
to both sides of the equation to get
2
x
2
+
x
−
5
=
5
−
5
2
x
2
+
x
−
5
=
0
Notice that you have
a
=
2
,
b
=
1
, and
c
=
−
5
. This means that the two solutions will be
x
1
,
2
=
−
1
±
√
1
2
−
4
⋅
2
⋅
(
−
5
)
2
⋅
2
x
1
,
2
=
−
1
±
√
41
4
You can simplify this if you want to get
x
1
=
−
1
+
√
41
4
≅
1.35078
and
x
2
=
−
1
−
√
41
4
≅
−
1.85078
Answer:
im sorry, the answer to what?
Answer:
19.8839 miles away
Step-by-step explanation:
:)
We need to graph this equation:

Its solutions are the points through which it graph passes. Since it's a linear equation its graph is a straight line and we only need two of its points to draw it. But before graphing let's re-write the equation. We can substract 16x from both sides:

And we divide both sides by 2:

So now with this equation if we pick two random x values we'll get their corresponding y values. This way we'll find two points that are part of the graph which is the line that passes through both. We can begin with x=0:

So the first point is (0,150). Then we can take x=10 and we get:

So the second point is (10,70). Then the graph is the line that passes through points (0,150) and (10,70). In order to represent it
Answer:
Step-by-step explanation:
(12 - 2)/(2 - 7) = 10/-5 = -2
y - 12 = -2(x - 2)
y - 12 = -2x + 2
y = -2x + 14