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3 years ago

Subtract. 1/6 −(−7 1/3 )

Mathematics

1 answer:

Leokris [45]3 years ago

4 0

Answer:

The answer is 7 1/2 or 15/2 or 7.5 (all the same just in mixed fraction and decimal form)

Step-by-step explanation:

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HELP ASAP PLEASE!!! AND PLEASE SHOW WORK 1. 20% OF ____= 40 2. 30% OF ____=90

lesya692 [45]

Answer: 1. 200, 2. 300

Step-by-step explanation:

40 * 10/2 = 400/2 = 200

or this way:

40 = 20%

40/2 = 20

20 = 10%

20 * 10 = 200

——————————————

90 * 10/3 = 900/3 = 300

or this way:

90 = 30%

90/3 = 30

30 = 10%

30 * 10 = 300

8 0

3 years ago

Read 2 more answers

Uh oh got negative points on another acc but ay im here on a different one uhhhhhhhhhhhh

Mekhanik [1.2K]

Answer:

whyd you post this thx 4 the points tho

Step-by-step explanation:

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3 years ago

A school baseball team has 65 players. What is the probability that a randomly chosen player is a junior or a right handed batte

iragen [17]

Answer:

$Probability = \frac{51}{65}$

Step-by-step explanation:

Given (Missing from the question)

$\begin{array}{ccccc}{} & {Freshman} & {Sophomore} & {Junior} & {Senior} &{Left-handed batters} & {4} & {6} & {5} & {4} & {Right-handed batters} & {13} & {10} & {11} & {12}\ \end{array}$

$Total = 65$

Required

Determine the probability of selecting a junior or right handed batter

From the table above:

$R=13 + 10 + 11 + 12 =46$ ---- Right handed

$J = 5 + 11 = 16$ --- Junior

$R\ and\ J = 11$ ---- Right handed and Junior

The probability of right handed player of junior player being selected is:

$Probability = P(R) + P(J) - P(R\ and\ J)$

$Probability = \frac{n(R) + n(J) - n(R\ and\ J)}{Total}$

$Probability = \frac{46+16-11}{65}$

$Probability = \frac{51}{65}$

3 0

3 years ago

Last question im putting all my points into this pleae help! 50 points!

AysviL [449]

Answer:

10 inches

Step-by-step explanation:

refer the image

5 0

2 years ago

Perform the indicated operation. (-7) · (-5) -12 -35 12 35

Tanya [424]

35, because two negatives when multiplied is equal to a positive

3 0

3 years ago