B^-2 / b^-3 = b^(-2-(-3) = b^1 = b
answer is d
3:1 should be the answer.
H=0
Therefore:
144t-16t²=0
t (144-16t)=0
We have two equations:
1)
t=0 (when the ball is released)
2)
144-16t=0
-16t=-144
t=-144 / -16=9 (this is the time )
Answer: the ball hit the ground in 9 s.
Answer:
-2/3
Step-by-step explanation:
The gradient of a line is its slope. You can just convert the equation to slope-intercept form (y=mx+b where "m" is the gradient/slope):
3y + 2x = 1
3y = 1 - 2x
y = 1/3 - 2/3x
y = -2/3x + 1/3
So, as we can see, -2/3 is the gradient/slope of the line.
Answer:
Option C - $26.44
Step-by-step explanation:
To find the closing proce on Wednesday
Company XYZ is $ 25.69 on Thursday
Company XYZ is - $0.75 on Wednesday
This means the calculation should be as following,
25.69 + 0.75 = 26.44$ the closing price for Wednesday
