Answer:
y=20(6)^x
Step-by-step explanation:
hello :
the graph passes through the point (0,20) : when x=0 and y=20 :
20= ab^0 so a=20 because : b^0 = 1
the graph passes through the point (3,4320) : when x=3. and y=4320 : 4320= ab^3 but : a=20 so : 4320 = 20b^3
so : b^3 = 4320/20 = 216...... 216 = 6^3
b^3 = 6^3
b=6
the function is : y=20(6)^x
So you subtract 64.50 - 47.10 and it equals 17.4 and then you divide that by 4 and your answer is 4.35
The order of the values using the basic unit of meters from smallest to largest. is: 109000 mm < 2.6 km < 41.7 hm
What are the units of measurement of distance or length?
Distance is the gap between any two points under consideration.
The basic unit for measuring distance is the meter.
There are larger as well as smaller units for measuring length or distance which are based on the unit of meter.
The units are as follows:
millimeter, mm = 0.001 m
centimeter, cm = 0.01 m
decimeters, dm = 0.1 m
meter, m = 1 m
kilometer, km = 1000 m
hectometer, hm = 100 m
Now to compare the given quantities making the units same as two quantities can only be compared only when there units are same :
Considering the given values;
2.6 km = 2600 m
109,000 mm = 109 m
41.7 hm = 4170 m
Therefore, after comparison arranging the quantities in order from smallest to largest is 109000 mm < 2.6 km < 41.7 hm
Learn more about quantities at:
brainly.com/question/13421174
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We have that
<span>(c-4)/(c-2)=(c-2)/(c+2) - 1/(2-c)
</span>- 1/(2-c)=-1/-(c-2)=1/(c-2)
(c-4)/(c-2)=(c-2)/(c+2)+ 1/(c-2)------- > (c-4)/(c-2)-1/(c-2)=(c-2)/(c+2)
(c-4-1)/(c-2)=(c-2)/(c+2)---------------- > (c-5)/(c-2)=(c-2)/(c+2)
(c-5)/(c-2)=(c-2)/(c+2)------------- > remember (before simplifying) for the solution that c can not be 2 or -2
(c-5)*(c+2)=(c-2)*(c-2)------------------ > c²+2c-5c-10=c²-4c+4
-3c-10=-4c+4----------------------------- > -3c+4c=4+10----------- > c=14
the solution is c=14
the domain of the function is (-∞,-2) U (-2,2) U (2,∞) or
<span>all real numbers except c=-2 and c=2</span>
Answer:
D/0
Step-by-step explanation:
the domain of (g o f )(x) is "all x > 0".
